제출 #885286

#제출 시각아이디문제언어결과실행 시간메모리
88528642kangarooBeech Tree (IOI23_beechtree)C++17
5 / 100
196 ms149720 KiB
//  D. Beech Tree

#include<bits/stdc++.h>
#include "beechtree.h"

using namespace std;

using g_t = vector<vector<int>>;
using dVal = tuple<map<int, int>, list<set<pair<int, int>>>, int>;

dVal dfs(int n, g_t &g, vector<bool> &po, vector<int> &c) {
	map<int, int> r;
	map<int, vector<pair<int, int>>> ve;
	list<set<pair<int, int>>> se;
	int seSi = 0;
	for (auto e: g[n]) {
		if (r.find(c[e]) != r.end()) po[n] = false;
		r[c[e]] = 1;
		ve[c[e]] = {};
	}
	for (auto e: g[n]) {
		auto [re, li, si] = dfs(e, g, po, c);
		if (!po[e]) {
			po[n] = false;
		}
		if (!po[n]) continue;
		for (auto &[co, d]: re) {
			if (r.find(co) == r.end()) {
				po[n] = false;
				break;
			}
			if (co == c[e]) r[c[e]] = d + 1;
			ve[co].emplace_back(d, e);
		}
		if (!po[n]) continue;
		if (si > seSi) {
			swap(se, li);
			swap(si, seSi);
		}
		auto itS = se.begin();
		for (auto &it: li) {
			assert(itS->empty());
			while (itS != se.end() && itS->size() <= it.size()) {
				for (auto cos: *itS) {
					if (it.erase(cos) == 0) {
						po[n] = false;
						break;
					}
				}
				if (!po[n]) break;
				itS++;
			}
			if (!po[n]) break;
			if (!it.empty()) {
				auto act = itS;
				itS = se.insert(itS, set<pair<int, int>>());
				for (auto cos: it) {
					if (act->erase(cos) == 0) {
						po[n] = false;
						break;
					}
					itS->insert(cos);
				}
			}
			if (!po[n]) break;
		}
	}
	if (!po[n]) return {};
	se.emplace_back();
	for (auto &[co, vec]: ve) {
		bool dD = true;
		for (auto [d, e]: vec) {
			if (d > r[co]) {
				po[n] = false;
				return {};
			} else if (d == r[co]) {
				dD = false;
				break;
			}
		}
		if (dD) {
			se.back().insert({co, r[co]});
			seSi++;
		}
	}
	if (se.back().empty()) se.pop_back();
	return {std::move(r), std::move(se), seSi};
}

vector<int> beechtree(int N, int M, vector<int> P, vector<int> C) {
	g_t g(N);
	for (int i = 1; i < N; ++i) {
		g[P[i]].push_back(i);
	}
	vector<bool> po(N, true);
	dfs(0, g, po, C);
	return {po.begin(), po.end()};
}

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