이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
int n;
int a[1000010],st[1000010];
int tree[4000040],tree1[4000040];
void build_tree(int v, int tl, int tr) {
if (tl == tr) {
tree[v] = a[tl];
} else {
int tm = (tl + tr) / 2;
build_tree(v * 2, tl, tm);
build_tree(v * 2 + 1, tm + 1, tr);
tree[v] = min(tree[v * 2], tree[v * 2 + 1]);
}
}
void build_tree1(int v, int tl, int tr) {
if (tl == tr) {
tree1[v] = a[tl];
} else {
int tm = (tl + tr) / 2;
build_tree1(v * 2, tl, tm);
build_tree1(v * 2 + 1, tm + 1, tr);
tree1[v] = max(tree1[v * 2], tree1[v * 2 + 1]);
}
}
int get_min(int l, int r, int v, int tl, int tr) {
if (l <= tl && tr <= r) {
return tree[v];
}
if (tr < l || r < tl) {
return INT_MAX;
}
int tm = (tl + tr) / 2;
return min(get_min(l, r, v * 2, tl, tm),
get_min(l, r, v * 2 + 1, tm + 1, tr));
}
int get_max(int l, int r, int v, int tl, int tr) {
if (l <= tl && tr <= r) {
return tree1[v];
}
if (tr < l || r < tl) {
return 0;
}
int tm = (tl + tr) / 2;
return max(get_max(l, r, v * 2, tl, tm),
get_max(l, r, v * 2 + 1, tm + 1, tr));
}
int main(){
ios::sync_with_stdio(false);
cin.tie(0); cout.tie(0);
int n,m;
cin >> n >> m;
for(int i=0;i<n;i++){
cin >> a[i];
}
build_tree(1, 0, n - 1);
build_tree1(1, 0, n - 1);
st[0]=0;
for(int i=0;i<n-1;i++){
if(a[i+1]>=a[i]){
st[i+1]=st[i]+1;
}
else{
st[i+1]=0;
}
}
for(int i=0;i<m;i++){
int l,r,k;
cin >> l >> r >> k;
if(get_min(l-1,r-1,1,0,n-1)+get_max(l-1,r-1,1,0,n-1)<=k){
cout << 1 << endl;
}
else{
cout << 0 << endl;
}
}
}
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