이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#define F first
#define S second
#define ll long long
#define pb push_back
#define pii pair<int, int>
#define a3 pair<pair<int, int>, int>
const int K = 1e5 + 4, M = 1e9 + 7;
int n, m, k;
a3 know[K];
int power(int a, ll b, int mod = M) {
int ret = 1;
for (; b; b >>= 1, a = 1ll * a * a % mod)
if (b & 1)
ret = 1ll * ret * a % mod;
return ret;
}
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cin >> n >> m >> k;
for (int i = 0; i < k; ++i) {
char c;
cin >> c;
if (c == '+') {
know[i].S = 1;
}
cin >> know[i].F.F >> know[i].F.S;
}
sort(know, know + k);
int last = 1, it = 0, dp[] = {1, 1}, d[] = {1, 1};
know[k] = {{n + 1, 0}, -1};
while (it <= k) {
if (know[it].F.F != last) {
if (last == 1) {
dp[0] = d[0];
dp[1] = d[1];
}
else {
int save[] = {dp[0], dp[1]};
dp[0] = d[0] * (save[0] + save[1]) % M;
dp[1] = d[1] * (save[0] + save[1]) % M;
}
int free = know[it].F.F - last - 1;
if (free > 0) {
dp[0] = dp[1] = 1ll * (dp[0] + dp[1]) * power(2, free - 1) % M;
}
d[0] = d[1] = 1;
last = know[it].F.F;
}
if (know[it].S == 1) {
d[know[it].F.S % 2] = 0;
}
else if (know[it].S == 0) {
d[!(know[it].F.S % 2)] = 0;
}
++it;
}
int ans = (dp[0] + dp[1]) % M;
// cerr << ans << ' ';
for (int i = 0; i < k; ++i) {
if (know[i].F.F % 2 == 0) {
know[i].S = !know[i].S;
}
know[i].F.F = 1;
}
sort(know, know + k);
d[0] = 1;
d[1] = 1;
int D = 1, free = m;
pii before = {0, 0}; // (x, state)
for (int i = 0; i < k; ++i) {
pii cur = {know[i].F.S, know[i].S};
if (cur.F == before.F && cur.S != before.S) {
D = 0;
}
if (cur.F != before.F) {
--free;
before = cur;
}
if (cur.S == 1) {
d[cur.F % 2] = 0;
}
else if (cur.S == 0) {
d[!(cur.F % 2)] = 0;
}
}
int add = D * ((power(2, free) - d[0] - d[1] + M) % M) % M;
ans = (ans + add) % M;
cout << ans;
return 0;
}
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