이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std ;
using ll = long long ;
struct SegTree {
int _n ;
struct Node {
ll value = 0 ;
Node() {}
Node(ll x) {
value = x ;
}
};
Node combine(Node l, Node r) {
if (l.value > r.value) return l ;
return r ;
}
vector<Node> t ;
SegTree(int len) {
_n = len ;
t.assign(len * 4 + 1, Node(0)) ;
}
void modify(int i, ll x, int v, int tl, int tr) {
if (tl == tr) {
t[v] = combine(x, t[v]) ;
} else {
int tm = (tl + tr) >> 1 ;
if (i <= tm)
modify(i, x, v << 1, tl, tm) ;
else
modify(i, x, v << 1 | 1, tm + 1, tr) ;
t[v] = combine(t[v * 2], t[v * 2 + 1]) ;
}
}
void modify(int i, ll x) {
modify(i, x, 1, 1, _n) ;
}
Node get(int l, int r, int v, int tl, int tr) {
if (l > tr || r < tl) return Node(0) ;
if (l <= tl && tr <= r) return t[v] ;
int tm = (tl + tr) >> 1 ;
Node L = get(l, r, v << 1, tl, tm) ;
Node R = get(l ,r, v << 1 | 1, tm + 1, tr) ;
return combine(L, R) ;
}
Node get(int l, int r) {
if (l > r) return Node(0) ;
return get(l, r, 1, 1, _n) ;
}
};
int32_t main() {
ios::sync_with_stdio(false) ;
cin.tie(nullptr) ;
int n , x ;
cin >> n >> x ;
vector<int> a(n + 1), c ;
for (int i = 1 ; i <= n ; i++) {
cin >> a[i] ;
c.push_back(a[i]) ;
c.push_back(a[i] - 1) ;
c.push_back(a[i] + 1) ;
}
sort(c.begin(), c.end()) ;
c.erase(unique(c.begin(), c.end()), c.end()) ;
auto get = [&](int i) -> int {
return (lower_bound(c.begin(), c.end(), i) - c.begin() + 1) ;
};
int m = c.size() ;
SegTree s(m) ;
vector<int> pre(n + 1, 1), suf(n + 1, 1) ;
for (int i = 1 ; i <= n ; i++) {
pre[i] = max(pre[i] * 1ll, s.get(1, get(a[i] - 1)).value + 1) ;
s.modify(get(a[i]), pre[i]) ;
}
s = SegTree(m) ;
for (int i = n ; i >= 1 ; i--) {
suf[i] = max(suf[i] * 1ll, s.get(get(a[i] + 1), m).value + 1) ;
s.modify(get(a[i]), suf[i]) ;
}
int ret = 0 ;
for (int i = 1 ; i <= n ; i++) {
for (int j = i + 1 ; j <= n ; j++) {
if (a[j] - 1 >= a[i] - x && a[j] - 1 <= a[i] + x) {
ret = max(ret, pre[i] + suf[j]) ;
}
if (a[i] - 1 >= a[j] - x && a[i] - 1 <= a[j] + x) {
ret = max(ret, pre[i] + suf[j]) ;
}
}
ret = max(ret, pre[i]) ;
}
cout << ret ;
return 0 ;
}
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