This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#ifdef OP_DEBUG
#include <algo/debug.h>
#else
#define debug(...) 26
#endif
using namespace std;
#define int long long // maybe tle?
#define sz(v) (int)(v).size()
#define all(v) (v).begin(), (v).end()
#define TcT template <class T
const int MOD = (int)1e9 + 7, INF = (int)2e9 + 9, INF64 = (int)4e18 + 18;
TcT> bool minimize(T &val, const T &upd) { return upd < val ? val = upd, 1 : 0; }
TcT> bool maximize(T &val, const T &upd) { return upd > val ? val = upd, 1 : 0; }
TcT, class S> istream &operator >> (istream &scanf, pair <T, S> &u) { return scanf >> u.first >> u.second; }
TcT, class S> ostream &operator << (ostream &print, pair <T, S> &u) { return print << u.first << ' ' << u.second; }
void solve();
int32_t main() {
cin.tie(nullptr), cout.tie(nullptr) -> sync_with_stdio(0);
int testcases = 1;
#define TC 0
if (TC) { cin >> testcases; } for (; testcases--;) { solve(); }
}
/* [Pham Hung Anh - 11I - Tran Hung Dao High School for Gifted Student] */
int k, n;
namespace sub12 {
void solve() {
int ans = 0;
vector <int> buildings;
for (int i = 1; i <= n; ++i) {
char p, q; int s, t; cin >> p >> s >> q >> t;
if (p == q)
ans += abs(s - t);
else
buildings.push_back(s), buildings.push_back(t);
}
sort(all(buildings));
int m = sz(buildings);
int median = buildings[(m + 1) / 2];
for (int i = 0; i < m; ++i)
ans += abs(median - buildings[i]);
cout << ans + sz(buildings) / 2 << '\n';
}
}
namespace sub3 {
void solve() {
int ans = 0;
vector <int> buildings;
vector <pair <int, int>> opposite;
for (int i = 1; i <= n; ++i) {
char p, q; int s, t; cin >> p >> s >> q >> t;
if (p == q)
ans += abs(s - t);
else
buildings.push_back(s), buildings.push_back(t), opposite.emplace_back(min(s, t), max(s, t));
}
int res = INF;
for (int i = 0; i < sz(buildings); ++i)
for (int j = i + 1; j < sz(buildings); ++j) {
int r1 = buildings[i], r2 = buildings[j];
int sum = 0;
for (auto p : opposite)
sum += min(abs(p.first - r1) + abs(p.second - r1), abs(p.first - r2) + abs(p.second - r2)) + 1;
minimize(res, sum);
}
cout << ans + res << '\n';
}
}
namespace sub4 {
void solve() {
}
}
void solve() {
cin >> k >> n;
if (k == 1)
sub12 :: solve();
else {
if (n <= 100)
sub3 :: solve();
else if (n <= 1000)
sub4 :: solve();
}
}
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