이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
int n, m, k, q;
typedef array<int, 3> arr3;
map<arr3, int> arr;
int query(int i, int j = 0, int k = 0) {
if (i < 0 || i >= n || j < 0 || j >= m || k < 0 || k >= m) return 0;
if (arr.find(arr3({i, j, k})) == arr.end()) {
q--;
assert(q >= 0);
cout << "? " << i+1 << ' ' << j+1 << ' ' << k+1 << endl;
cin >> arr[arr3({i, j, k})];
}
return arr[arr3({i, j, k})];
}
int query(arr3 a) {
return query(a[0], a[1], a[2]);
}
void make_answer(int i, int j = 0, int k = 0) {
cout << "! " << i+1 << ' ' << j+1 << ' ' << k+1 << '\n';
}
void make_answer(arr3 a) {
return make_answer(a[0], a[1], a[2]);
}
void sol1d() {
assert(m == 1); assert(k == 1);
int l = -1, r = n;
while (r > l) {
if (r-l == 1) {
if (query(r) > query(l)) l = r;
else r = l;
}
else if (r-l == 2) {
query(l+1);
int v = l;
for (int i = l+1; i <= r; i++) if (query(i) > query(v)) v = i;
l = r = v;
}
else if (r-l == 3) {
if (query(l) >= query(r)) {
if (query(l) >= query(l+1)) r = l;
else if (query(l+1) >= query(l+2)) l = r = l+1;
else if (query(l+2) >= query(r)) l = r;
}
else {
if (query(r) >= query(r-1)) l = r;
else if (query(r-1) >= query(r-2)) l = r = r-1;
else if (query(r-2) >= query(l)) r = l;
}
}
else {
if (query(l) < query(r)) { // right thing has to be strictly greater
int i = r-(r-l+2)/3;
int j = (l+i+1)/2;
if (query(i) < query(r)) {
l = i;
}
else {
if (query(i) > query(j)) {
if (query(i+1) > query(i)) l = i+1;
else {
l = j;
r = i;
}
}
else {
if (query(j-1) >= query(j)) {
r = j-1;
}
else {
l = j;
r = i;
}
}
}
}
else { // right thing has to be strictly greater
int i = l+(r-l+2)/3;
int j = (r+i)/2;
if (query(i) <= query(l)) {
r = i;
}
else {
if (query(i) >= query(j)) {
if (query(i-1) >= query(i)) r = i-1;
else {
l = i;
r = j;
}
}
else {
if (query(j+1) > query(j)) {
l = j+1;
}
else {
l = i;
r = j;
}
}
}
}
// = (query(l) >= query(r) ? : r-(r-l+2)/3);
// int j = (query(l) >= query(r) ? (r+i)/2 : (l+i)/2);
// if (query(i))
}
}
make_answer(l);
}
void sol2d() {
assert(n == m); assert(k == 1);
int x1 = -1, x2 = n, y1 = -1, y2 = n;
int mxa = -1, mxb = -1;
while (x1+1 < x2 && y1+1 < y2) {
if (x2 - x1 < y2-y1) {
int y = (y1+y2)/2;
int v = x1;
for (int i = x1; i <= x2; i++) {
if (query(i, y) > query(v, y)) v = i;
}
/*
extra condition -- if cur global max is > than max discovered,
we choose the side with global max on it
*/
if (query(mxa, mxb) >= query(v, y)) {
if (mxb <= y) y2 = y;
else y1 = y;
}
else {
mxa = v;
mxb = y;
if (query(v, y) >= query(v, y+1)) y2 = y;
else y1 = y; // not worth it
}
}
else {
int x = (x1+x2)/2;
int v = y1;
for (int i = y1; i <= y2; i++) {
if (query(x, i) > query(x, v)) v = i;
}
if (query(mxa, mxb) >= query(x, v)) {
if (mxa <= x) x2 = x;
else x1 = x;
}
else {
mxa = x;
mxb = v;
if (query(x, v) >= query(x+1, v)) x2 = x;
else x1 = x; // not worth it
}
}
}
int a = x1, b = y1;
for (int i = x1; i <= x2; i++) {
for (int j = y1; j <= y2; j++) {
if (query(i, j) > query(a, b)) {
a = i; b = j;
}
}
}
make_answer(a, b);
}
arr3 operator+(arr3 a, arr3 b) {
return arr3({a[0]+b[0], a[1]+b[1], a[2]+b[2]});
}
vector<arr3> adj(6);
void sol3d() {
assert(n == m); assert(m == k);
int u = q/2;
mt19937 gen(0);
arr3 mx({-1, -1, -1});
for (int i = 0; i < u; i++) {
int x, y, z;
do {
x = gen()%n; y = gen()%n; z = gen()%n;
} while (arr.find(arr3({x, y, z})) != arr.end());
if (query(x, y, z) > query(mx)) mx = arr3({x, y, z});
}
adj[0] = arr3({1, 0, 0});
adj[1] = arr3({-1, 0, 0});
adj[2] = arr3({0, 1, 0});
adj[3] = arr3({0, -1, 0});
adj[4] = arr3({0, 0, 1});
adj[5] = arr3({0, 0, -1});
while (1) {
arr3 nxt = mx;
for (int i = 0; i < 6; i++) {
if (query(mx+adj[i]) > query(nxt)) nxt = mx+adj[i];
}
if (nxt == mx) break;
mx = nxt;
}
make_answer(mx);
}
int main() {
cin >> n >> m >> k >> q;
if (m == 1 && k == 1) sol1d();
else if (k == 1) sol2d();
else sol3d();
}
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