이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <iostream>
#include <fstream>
#include <set>
#include <map>
#include <string>
#include <vector>
#include <bitset>
#include <algorithm>
#include <cstring>
#include <cstdlib>
#include <cmath>
#include <cassert>
#include <queue>
#define mp make_pair
#define pb push_back
typedef long long ll;
typedef long double ld;
using namespace std;
char ans[100];
int n;
string s[120];
vector<int> eds[100];
int p[120];
int was[120];
vector<int> vv;
void dfs1(int v) {
was[v] = 1;
for (int u: eds[v]) {
if (!was[u])
dfs1(u);
else if (was[u] == 1) {
cout << "NE\n";
exit(0);
}
}
vv.push_back(v);
was[v] = 2;
}
int main() {
cin >> n;
for (int i = 0; i < n; ++i)
cin >> s[i];
for (int i = 0; i < n; ++i)
cin >> p[i], --p[i];
for (int i = 0; i < n - 1; ++i) {
int kk = min(s[p[i]].size(), s[p[i + 1]].size());
for (int j = 0; j < kk; ++j) {
if (s[p[i]][j] != s[p[i + 1]][j]) {
kk = j;
break;
}
}
if (kk == (int)s[p[i + 1]].size()) {
cout << "NE\n";
return 0;
}
if (kk == (int)s[p[i]].size())
continue;
eds[s[p[i + 1]][kk] - 'a'].push_back(s[p[i]][kk] - 'a');
}
for (int i = 0; i < 26; ++i)
if (!was[i])
dfs1(i);
for (int i = 0; i < (int)vv.size(); ++i) {
ans[vv[i]] = 'a' + i;
}
printf("DA\n");
printf("%s\n", ans);
return 0;
}
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