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Submission #881074

# Submission time Handle Problem Language Result Execution time Memory
881074 2023-11-30T14:16:38 Z alexdd Skyline (IZhO11_skyline) C++17
0 / 100
 2000 ms 47452 KB 
#include<bits/stdc++.h>
using namespace std;
const int INF = 1e9;
int n;
int dp[315][205][205];
int h[315];
signed main()
{
    cin>>n;
    for(int i=1;i<=n;i++)
    {
        cin>>h[i];
    }
    for(int i=1;i<=n+2;i++)
        for(int u=0;u<=200;u++)
            for(int j=0;j<=200;j++)
                dp[i][u][j]=INF;
    dp[2][h[1]][h[2]]=0;
    for(int i=2;i<=n+1;i++)
    {
        for(int j=0;j<=200;j++)
        {
            for(int k=0;k<=200;k++)
            {
                int p=j,u=k;
                if(dp[i][p][u]==INF)
                    continue;
                for(int cnt3=0;cnt3<=min(h[i+1],min(p,u));cnt3++)
                {
                    for(int cnt2=0;cnt2+cnt3<=min(p,u);cnt2++)
                    {
                        dp[i+1][u-cnt2-cnt3][h[i+1]-cnt3] = min(dp[i+1][u-cnt2-cnt3][h[i+1]-cnt3], dp[i][p][u] + (p-cnt2-cnt3)*3 + cnt2*5 + cnt3*7);
                    }
                }
                /*int nxt = h[i+1];
                int cnt3 = min({p,u,nxt});
                p -= cnt3;
                u -= cnt3;
                nxt -= cnt3;
                int cnt2 = min(p,u);
                p -= cnt2;
                u -= cnt2;
                int cnt1 = p;
                p -= cnt1;
                dp[i+1][u][nxt] = min(dp[i+1][u][nxt], dp[i][j][k] + cnt1*3 + cnt2*5 + cnt3*7);

                p=j;
                u=k;
                nxt=h[i+1];
                cnt2 = min(p,u);
                p -= cnt2;
                u -= cnt2;
                cnt1 = p;
                p -= cnt1;
                dp[i+1][u][nxt] = min(dp[i+1][u][nxt], dp[i][j][k] + cnt1*3 + cnt2*5);

                p=j;
                u=k;
                cnt1 = p;
                p -= cnt1;
                dp[i+1][u][nxt] = min(dp[i+1][u][nxt], dp[i][j][k] + cnt1*3);*/
            }
        }
    }
    cout<<min({dp[n][0][0],dp[n+1][0][0],dp[n+2][0][0]});
    return 0;
}
/**

dp[i][p][u] = costul minim pentru a construi toate cladirile 1..i-2, iar cladirea i-1 sa mai aiba nevoie de p inaltime, iar cladirea i de u inaltime
dp[i+1][

dp[i][p][u] = min(dp[i-1][])

*/

Subtask #1
0 / 100.0

# Verdict Execution time Memory Grader output
1 Correct 1 ms 2396 KB Output is correct
2 Correct 1 ms 2396 KB Output is correct
3 Correct 1 ms 2392 KB Output is correct
4 Correct 5 ms 12632 KB Output is correct
5 Correct 1 ms 2392 KB Output is correct
6 Correct 1 ms 2396 KB Output is correct
7 Correct 1 ms 2396 KB Output is correct
8 Correct 5 ms 2396 KB Output is correct
9 Correct 28 ms 4440 KB Output is correct
10 Correct 89 ms 6596 KB Output is correct
11 Correct 429 ms 25076 KB Output is correct
12 Correct 250 ms 6492 KB Output is correct
13 Correct 553 ms 29020 KB Output is correct
14 Correct 1472 ms 35328 KB Output is correct
15 Execution timed out 2056 ms 47452 KB Time limit exceeded
16 Halted 0 ms 0 KB -