이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#pragma GCC optimize("Ofast","unroll-loops")
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/detail/standard_policies.hpp>
using namespace std;
using namespace __gnu_pbds;
typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> ost;
#define endl "\n"
#define ll long long
#define ull unsigned long long
#define ld long double
#define pi pair<int,int>
#define pll pair<long long,long long>
#define vi vector<int>
#define vll vector<long long>
#define vpi vector<pair<int,int>>
#define vpll vector<pair<long long,long long>>
#define vvi vector<vector<int>>
#define vvll vector<vector<long long>>
#define vr vector<range<int>>
#define cd complex<double>
#define pb push_back
template<typename T>
struct matrix{
vector<T> mtx;
T Tdef;
int column=-1,row=-1;
matrix() {}
matrix(int r,int c) {
mtx.assign(r*c,Tdef);
row = r;
column = c;
}
matrix(int r,int c,T val){
mtx.assign(r*c,val);
row = r;
column = c;
}
struct proxy{
matrix *m ;
int i;
proxy(matrix* x , int y) : m(x) , i(y){}
T &operator[] (int j){
return (m->mtx[i*(m->row) + j]);
}
};
proxy operator[](int i){
return proxy(this,i);
}
void fill(T x){for(auto &y:mtx)y=x;}
void fill_row(int rw,T x,int l=0,int r=-1){
if(r==-1)r = column-1;
for(int i=l;i<=r;i++){
mtx[rw*row + i] = x;
}
}
void fill_column(int cl,T x,int l=0,int r=-1){
if(r == -1)r = row-1;
for(int i=l;i<=r;i++){
mtx[i*row + cl] = x;
}
}
void inc_row(int rw,T x,int l=0,int r=-1){
if(r==-1)r = column-1;
for(int i=l;i<=r;i++){
mtx[rw*row + i] += x;
}
}
void inc_column(int cl,T x,int l=0,int r=-1){
if(r == -1)r = row-1;
for(int i=l;i<=r;i++){
mtx[i*row + cl] +=x;
}
}
int count(int rw,T x,int l=0,int r=-1){
if(r == -1)r = column-1;
int cnt = 0;
for(int i=l;i<=r;i++)cnt += (mtx[rw*row + i] == x);
return cnt;
}
};
template<typename V,typename S> istream& operator >> (istream &x,pair<V,S> &p){cin >> p.first >> p.second ;return x;}
template<typename V,typename S> ostream& operator << (ostream &x,const pair<V,S> &p){cout << p.first <<" "<<p.second;return x;}
#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL)
#define abs(x) ((x)>0?(x):-((x)))
#define fr(i,j) for(int i=0;i<j;i++)
#define frt(a,b,c) for(int a=b;a<c;a++)
#define fra(x,y) for(auto &x:y)
#define min(a,b) ((a)<(b)?(a):(b))
#define all(x) x.begin(),x.end()
int mlog(int x) {
return 32 - __builtin_clz(x) - 1;
}
ll sum(ll a,ll b,ll M=1e+9+7){
a%=M;b%=M;return (a+b)%M;
}
ll subs(ll a,ll b,ll M=1e+9+7){
a-=b;a%=M;if(a<0)a+=M;return a;
}
ll mult(ll a,ll b,ll M=1e+9+7){
a%=M;b%=M;return (a*b)%M;
}
ll bp(ll a,ll b,ll M=1e+9+7){
if(b == 0)return 1;
if(b == 1)return a;
ll x = bp(a,b/2,M);
x = mult(x,x,M);
if(b%2)x=mult(x,a,M);
return x;
}
#include "tickets.h"
ll find_maximum(int k,vvi x){
fastio;
int n = x.size();
int m = x[0].size();
ll ans = 0;
vpi points(n,{k-1,m-1}); // maximum of minimum : p.first maximum of maximum : p.second
vvi isactive(n,vi(m,0));
fr(i,n)
fr(j,k){isactive[i][j] = 1;ans -= x[i][j];}
set<pair<ll,int>,greater<pair<ll,int>>> sst;
fr(i,n)sst.insert({x[i][points[i].first] + x[i][points[i].second],i});
for(int turn=0;turn<(n*k)/2;turn++){
auto it = *(sst.begin());
ans += it.first;
isactive[it.second][points[it.second].first]=0;
isactive[it.second][points[it.second].second]=1;
points[it.second].first--;points[it.second].second--;
sst.erase(sst.begin());
if(points[it.second].first < 0)continue;
sst.insert({x[it.second][points[it.second].first] + x[it.second][points[it.second].second],it.second});
}
fr(i,n){
int q = 0;
fr(j,m){
if(isactive[i][j] == 0)isactive[i][j]=-1;
else isactive[i][j] = q++;
}
}
allocate_tickets(isactive);
return ans;
}
/*int32_t main(){
fastio;
//cout << find_maximum(3,{{0,1,1,1},{0,1,1,1},{0,1,1,1},{0,0,0,1}});
}*/
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