#include <bits/stdc++.h>
#define fo(i, d, c) for (int i = d; i <= c; i++)
#define fod(i, c, d) for (int i = c; i >= d; i--)
#define maxn 200010
#define N 1010
#define fi first
#define se second
#define pb emplace_back
#define en cout << "\n";
#define int long long
#define inf 1000000000
#define pii pair<int, int>
#define vii vector<pii>
#define lb(x) x & -x
#define bit(i, j) ((i >> j) & 1)
#define offbit(i, j) (i ^ (1 << j))
#define onbit(i, j) (i | (1 << j))
#define vi vector<int>
template <typename T1, typename T2>
bool minimize(T1 &a, T2 b)
{
if (a > b)
{
a = b;
return true;
}
return false;
}
template <typename T1, typename T2>
bool maximize(T1 &a, T2 b)
{
if (a < b)
{
a = b;
return true;
}
return false;
}
using namespace std;
// struct BIT
// {
// int t[maxn];
// void up(int x, int val)
// {
// for (; x; x -= lb(x))
// t[x] = max(t[x], val);
// }
// int get(int x)
// {
// int ans = 0;
// for (; x < maxn; x += lb(x))
// ans = max(ans, t[x]);
// return ans;
// }
// };
struct BIT1
{
int t[200000];
void up(int x, int val)
{
for (; x < 200000; x += lb(x))
t[x] = max(val, t[x]);
}
int get(int x)
{
int ans = 0;
for (; x ; x -= lb(x))
ans = max(ans, t[x]);
return ans;
}
}t1;
int LIS(int arr[], int n)
{
fo(i,0,n) t1.t[i] = 0;
vi v;
fo(i, 1, n) v.pb(arr[i]);
sort(v.begin(), v.end());
v.erase(unique(v.begin(), v.end()), v.end());
int now = 0;
fo(i, 1, n)
{
int lb = lower_bound(v.begin(), v.end(), arr[i]) - v.begin() + 1;
int val = t1.get(lb) + 1;
now = max(now, val);
t1.up(lb + 1, val);
}
return now;
}
int n, x;
int a[maxn];
namespace sub2
{
int arr[maxn];
void solve()
{
int ans = 0;
// cout << "xxxx" << "\n";
fo(val, -x, x)
{
fo(i,1,n) arr[i] = a[i];
fo(l,1,n)
{
arr[l - 1] = a[l - 1];
fo(r,l,n)
{
arr[r] = a[r] + x;
ans = max(ans,LIS(arr,n));
}
}
}
cout << ans << "\n";
}
}
namespace sub4
{
void solve()
{
cout << LIS(a,n);
}
}
main()
{
#define name "TASK"
if (fopen(name ".inp", "r"))
{
freopen(name ".inp", "r", stdin);
freopen(name ".out", "w", stdout);
}
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cin >> n >> x;
fo(i, 1, n) cin >> a[i];
// cout << LIS(a,n) << "\n";
if(n <= 1000 and x <= 1000) sub2::solve();
else if(x == 0) sub4::solve();
}
