Submission #879950

#TimeUsernameProblemLanguageResultExecution timeMemory
879950amin_2008Bank (IZhO14_bank)C++17
100 / 100
969 ms5324 KiB
#pragma GCC optimize ("O3") #pragma GCC optimize("O3,unroll-loops") #pragma GCC target("avx,avx2,fma") #include <bits/stdc++.h> #include<ext/pb_ds/assoc_container.hpp> #include<ext/pb_ds/tree_policy.hpp> // author: amin_2008 #define ios ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0) #define ll long long #define vi vector<int> #define vs vector<string> #define vc vector<char> #define vl vector<ll> #define all(v) v.begin(), v.end() #define rall(v) v.rbegin(), v.rend() #define pb push_back #define bpc __builtin_popcount #define pii pair<int, int> #define pll pair<ll, ll> #define piii pair<pii, int> #define vpii vector<pii> #define vpll vector<pll> #define vvpii vector<vpii> #define vvi vector<vector<int>> #define vvl vector<vector<ll>> #define ins insert #define ts to_string #define F first #define S second #define lb lower_bound #define ub upper_bound #define ld long double #define ull unsigned long long #define endl '\n' #define int ll using namespace std; using namespace __gnu_pbds; using namespace __cxx11; template<class T> using ordered_set = tree<T, null_type,less<T>, rb_tree_tag,tree_order_statistics_node_update>; mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); const int inf = 1e18; const int mod = 1e9+7; const int sz = 2e5+5; const int N = 100005; const int logg = 18; const int P = 40000005; const int M = 5e5+5; int a[sz]; int b[sz]; void solve() { int n, m; cin >> n >> m; vi pref(n + 1); for(int i = 1; i <= n; i++) cin >> a[i], pref[i] = pref[i-1] + a[i]; for(int i = 0; i < m; i++) cin >> b[i]; vector<vector<bool>> dp(n + 1, vector<bool>( 1 << m )); for(int i = 0; i < ( 1 << m ); i++) dp[0][i] = true; for(int j = 0; j < ( 1 << m ); j++) { int s = 0; for(int i = 0; i < m; i++) if ( ( j >> i ) & 1 ) s += b[i]; for(int i = 1; i <= n; i++) { if ( s == pref[i] and dp[i-1][j] ) dp[i][j] = true; for(int k = 0; k < m; k++) if ( ( ( j >> k ) & 1 ) and dp[i][j - ( 1 << k )] ) dp[i][j] = true; } } cout << ( count(all(dp[n]), true) ? "YES" : "NO" ) << endl; } signed main() { ios; //precompute(); int t = 1; //cin >> t; while(t--){ solve(); } }
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