이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define ll long long
#define pii pair<int, int>
#define all(v) v.begin(), v.end()
using namespace std;
const int oo = 2e9 + 1e8;
const int MAX = 2e5 + 5;
const int BLOCK = 2000;
pii arr[MAX];
int nxt = 1;
vector<pii> v;
struct DATA{
vector<int> a;
vector<int> b;
};
DATA combine(DATA& a, DATA& b){
DATA c;
c.a.resize(a.a.size() + b.a.size());
c.b.resize(a.b.size() + b.b.size());
merge(all(a.a), all(b.a), c.a.begin());
merge(all(a.b), all(b.b), c.b.begin());
return c;
}
DATA tree[MAX * 2];
void build(int node, int l, int r){
if(l == r){
tree[node].a.clear();
tree[node].b.clear();
tree[node].a = {v[l].second};
tree[node].b = {v[l].second - v[l].first + 1};
return;
}
int mid = (l + r) / 2;
build(node + 1, l, mid);
build(node + (mid - l + 1) * 2, mid + 1, r);
tree[node] = combine(tree[node + 1], tree[node + (mid - l + 1) * 2]);
}
int ask1(int node, int l, int r, int ql, int qr, int val){
if(ql > r || qr < l) return 0;
if(ql <= l && r <= qr){
auto itr = lower_bound(all(tree[node].a), val);
return (tree[node].a.end() - itr);
}
int mid = (l + r) / 2;
return ask1(node + 1, l, mid, ql, qr, val) + ask1(node + (mid - l + 1) * 2, mid + 1, r, ql, qr, val);
}
int ask2(int node, int l, int r, int ql, int qr, int val){
if(ql > r || qr < l) return 0;
if(ql <= l && r <= qr){
auto itr = lower_bound(all(tree[node].b), val);
return (tree[node].b.end() - itr);
}
int mid = (l + r) / 2;
return ask2(node + 1, l, mid, ql, qr, val) + ask2(node + (mid - l + 1) * 2, mid + 1, r, ql, qr, val);
}
vector<pii> b1;
vector<pii> b2;
void update(){
v.clear();
b1.clear();
b2.clear();
for (int i = 1; i < nxt; i++)
{
if(arr[i].first == -1) continue;
v.push_back(arr[i]);
}
cout << '\n';
sort(all(v));
build(0, 0, v.size() - 1);
}
int f(pii a, pii b){
int ans = min(a.second, b.second) - max(a.first, b.first) + 1;
if(ans <= 0) return 0;
return ans;
}
void solve(){
int n, o; cin >> n >> o;
int lastAns = 0;
while(n--){
int t; cin >> t;
if(t == 1){
int a, b; cin >> a >> b;
a = a ^ (o * lastAns);
b = b ^ (o * lastAns);
if(a > b) swap(a, b);
arr[nxt++] = {a, b};
b1.push_back({a, b});
}
else if(t == 2){
int id; cin >> id;
b2.push_back(arr[id]);
arr[id] = {-1, -1};
}
else{
int a, b, c; cin >> a >> b >> c;
a = a ^ (o * lastAns);
b = b ^ (o * lastAns);
if(a > b) swap(a, b);
if(b - a + 1 < c){
lastAns = 0;
cout << 0 << '\n';
continue;
}
if(b1.size() + b2.size() > BLOCK){
update();
}
int ans = 0;
if(v.size() != 0){
int i = lower_bound(all(v), make_pair(a, -1)) - v.begin();
if(i > 0){
ans += ask1(0, 0, v.size() - 1, 0, i - 1, a + c - 1);
}
int j = upper_bound(all(v), make_pair(b - c + 1, oo)) - v.begin();
if(j > 0 && i <= j - 1){
ans += ask2(0, 0, v.size() - 1, i, j - 1, c);
}
}
for(auto p:b1){
ans += (f(p, {a, b}) >= c);
}
for(auto p:b2){
ans -= (f(p, {a, b}) >= c);
}
lastAns = ans;
cout << ans << '\n';
}
}
}
/*
6 1
1 1 2
3 2 4 2
1 3 5
3 2 3 1
2 1
3 0 3 1
*/
/*
6 0
1 3 10
1 3 5
3 6 10 6
2 1
1 3 10
3 6 4 2
*/
int main()
{
solve();
}
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