제출 #879441

#제출 시각아이디문제언어결과실행 시간메모리
879441amin_2008Miners (IOI07_miners)C++17
100 / 100
94 ms201876 KiB
#pragma GCC optimize ("O3") #pragma GCC optimize("O3,unroll-loops") #pragma GCC target("avx,avx2,fma") #include <bits/stdc++.h> #include<ext/pb_ds/assoc_container.hpp> #include<ext/pb_ds/tree_policy.hpp> // author: amin_2008 #define ios ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0) #define ll long long #define vi vector<int> #define vs vector<string> #define vc vector<char> #define vl vector<ll> #define all(v) v.begin(), v.end() #define rall(v) v.rbegin(), v.rend() #define pb push_back #define bpc __builtin_popcount #define pii pair<int, int> #define pll pair<ll, ll> #define piii pair<pii, int> #define vpii vector<pii> #define vpll vector<pll> #define vvpii vector<vpii> #define vvi vector<vector<int>> #define vvl vector<vector<ll>> #define ins insert #define ts to_string #define F first #define S second #define lb lower_bound #define ub upper_bound #define ld long double #define ull unsigned long long #define endl '\n' #define int ll using namespace std; using namespace __gnu_pbds; using namespace __cxx11; template<class T> using ordered_set = tree<T, null_type,less<T>, rb_tree_tag,tree_order_statistics_node_update>; mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); const int inf = 1e9; const int mod = 1e9+7; const int sz = 3e5+5; const int N = 100005; const int logg = 18; const int P = 40000005; const int M = 5e5+5; int a[sz]; int dp[N][4][4][4][4]; int f(int x, int y, int z) { if ( x ) { if ( x == y and y == z ) return 1; else if ( ( x == y ) ^ ( y == z ) ^ ( z == x ) ) return 2; else return 3; } if ( y ) { if ( y == z ) return 1; else return 2; } return 1; } void solve() { int n; cin >> n; for(int i = 0; i <= n; i++) { for(int j = 0; j < 4; j++) { for(int k = 0; k < 4; k++) { for(int l = 0; l < 4; l++) { for(int m = 0; m < 4; m++) { dp[i][j][k][l][m] = -inf; } } } } } dp[0][0][0][0][0] = 0; for(int i = 1; i <= n; i++) { char c; cin >> c; int x = ( c == 'M' ? 1 : ( c == 'F' ? 2 : 3 )); for(int j = 0; j < 4; j++) { for(int k = 0; k < 4; k++) { for(int l = 0; l < 4; l++) { for(int m = 0; m < 4; m++) { dp[i][j][x][l][m] = max(dp[i][j][x][l][m], dp[i-1][k][j][l][m] + f(k, j, x)); } } } } for(int j = 0; j < 4; j++) { for(int k = 0; k < 4; k++) { for(int l = 0; l < 4; l++) { for(int m = 0; m < 4; m++) { dp[i][j][k][l][x] = max(dp[i][j][k][l][x], dp[i-1][j][k][m][l] + f(m, l, x)); } } } } } int res = 0; for(int i = 0; i < 4; i++) { for(int j = 0; j < 4; j++) { for(int k = 0; k < 4; k++) { for(int l = 0; l < 4; l++) { res = max(res, dp[n][i][j][k][l]); } } } } cout << res << endl; } signed main() { ios; //precompute(); int t = 1; //cin >> t; while(t--){ solve(); } }
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