This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "bits/stdc++.h"
using namespace std;
using ll = long long;
const int inf = 1e9;
const int lg = 20;
template<typename T> struct SegTree {
vector<T> tree;
int size;
T neutral_element = -1e9; // sum - 0, mx - (-INF), mn - INF
void init(int n) {
size = 1;
while (size <= n) size *= 2;
tree.assign(2 * size, neutral_element);
}
inline T type(T a, T b) {
return max(a, b);
}
SegTree(int n) {
init(n);
}
SegTree() {}
void set(int p, int value) { // set value at position p
p += size;
tree[p] = type(value, tree[p]);
for (; p > 1; p >>= 1) tree[p >> 1] = type(tree[p], tree[p ^ 1]);
}
T get(int l, int r) { // sum on interval [l, r]
if (l > r) return neutral_element;
int res = neutral_element;
for (l += size, r += size + 1; l < r; l >>= 1, r >>= 1) {
if (l & 1) res = type(res, tree[l++]);
if (r & 1) res = type(res, tree[--r]);
}
return res;
}
};
void solve() {
int n, q;
cin >> n >> q;
vector<int> a(n + 1), left(n + 1), ans(q);
stack<int> st;
vector<vector<int>> vec(n + 1);
vector<vector<tuple<int, int, int>>> queries(n + 1);
for (int i = 1; i <= n; i++) cin >> a[i];
for (int i = 0; i < q; i++) {
int l, r, k;
cin >> l >> r >> k;
queries[l].emplace_back(r, k, i);
}
for (int i = 1; i <= n; i++) {
while (!st.empty() and a[st.top()] <= a[i]) st.pop();
left[i] = st.empty() ? 0 : st.top();
vec[left[i]].emplace_back(i);
st.push(i);
}
SegTree<int> sg(n + 1);
for (int l = n; l > 0; l--) {
for (int i: vec[l]) sg.set(i, a[i] + a[left[i]]);
for (auto [r, k, i]: queries[l]) {
ans[i] = sg.get(l, r) <= k;
}
}
for (int i = 0; i < q; i++) cout << ans[i] << '\n';
}
int main() {
cin.tie(0)->sync_with_stdio(false);
#ifdef sunnatov
freopen("input.txt", "r", stdin);
freopen("output.txt", "w", stdout);
#endif
int queries = 1;
// cin >> queries;
for (int test_case = 1; test_case <= queries; test_case++) {
#ifdef sunnatov
cout << "Test case: " << test_case << endl;
#endif
solve();
cout << '\n';
}
}
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