답안 #878377

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
878377 2023-11-24T09:10:14 Z Parsa_Fallahpour Cities (BOI16_cities) C++17
100 / 100
3178 ms 54084 KB
/*
    Sag Template by ParsaF(RBS Master)
*/
 
// Heaven
 
#include <bits/stdc++.h>
/*
#pragma GCC optimize("O3,unroll-loops")
#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2")
#pragma GCC target("bmi,bmi2,lzcnt,popcnt")
#pragma GCC optimize("O3")
*/
using namespace std;
 
 
#define TOF_IO                                   ios_base::sync_with_stdio(false);cin.tie(0) , cout.tie(0);
#define File_IO(x,y)                             freopen(x, "r", stdin); freopen(y, "w", stdout);
 
#define SEP                                      ' '
#define endl                                     '\n'
 
#define F                                        first
#define S                                        second
#define ALL(x)                                   (x).begin(), (x).end()
#define sz(x)                                    (x).size()
#define PB                                       push_back
 
#define toLower(x)                               transform(ALL(x), x.begin(), ::tolower)
#define toUpper(x)                               transform(ALL(x), x.begin(), ::toupper)
 
#define EDGE(arr, x, y)                          arr[x].PB(y), arr[y].PB(x)
#define WEDGE(arr, x, y, z)                      arr[x].PB({y, z}), arr[y].PB({x, z})
 
#define debug(x)                                 cerr << #x << ": " << x << endl
#define kill(x)                                  cout << x << endl, exit(0);
 
#define BIPC(x)                                  __builtin_popcount(x);
 
#define fD1(arr, ind, x)                         for(int i=0; i<ind; i++) arr[i] = x;
#define fD2(arr, ind1, ind2, x)                  for(int i=0; i<ind1; i++) for(int j=0; j<ind2; j++) arr[i][j] = x;
 
#define lc                                       (id << 1)
#define rc                                       ((id << 1) | 1)
#define isLeaf                                   r - l == 1
 
typedef long long       ll; 
typedef long double     lld;
typedef pair<ll, ll>    pll;
typedef pair<int, int>  pii;
 
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
 
const ll N    = 1e5 + 20;
const ll MAXN = 10 + 5;
const ll MT   = 323 + 0;
const ll sq   = 320;
 
const ll M    = 1e8 + 0;
const ll IM   = 1e18 + 37;
 
const ll LOG  = 6;
 
const ll INF  = 1e18; 
const lld EPS = 0.00000001;
 
ll prime[] = {1000000009, 1000000007, 988244353, 1000696969, 696969569, 1223232323};
 
 
/***********************************************************       Dark side of Heaven        ************************************************************/
 
/***************************************************************************************************************************************************/
 
 
ll POW(ll a, ll b, ll md); 
ll LIS(vector<ll>& v);
ll MOD(ll a, ll b);
 
void printYES(bool flag);
void printYes(bool flag);
 
inline ll mod_add(ll a, ll b);
inline ll mod_neg(ll a, ll b);
inline ll mod_mlt(ll a, ll b);
 
/*
ll factI[N + 1], Numi[N + 1], fact[N + 1];
void InverseofNumber(ll p); void InverseofFactorial(ll p); void factorial(ll p); ll nPr(ll N, ll R, ll p); ll nCr(ll N, ll R); void comb();
*/

ll n, k, m;

ll C[6];

vector<pll> G1[N];

ll dp[(1<<LOG)][N];

void solve()
{
    cin >> n >> k >> m;
    
    for(int i=0; i<k; i++) cin >> C[i], C[i]--;
    
    for(int i=0; i<m; i++)
    {
        ll v, u, w;
        cin >> v >> u >> w; v--; u--;
        WEDGE(G1, v, u, w);
    }
    
    for(int mask=0; mask<(1<<k); mask++) for(int i=0; i<n; i++) dp[mask][i] = INF;
    
    for(int i=0; i<k; i++) dp[(1<<i)][C[i]] = 0;
    
    for(int mask=1; mask<(1<<k); mask++)
    {
        for(int i=0; i<k; i++) if((mask>>i)&1) for(int v=0; v<n; v++) dp[mask][v] = min(dp[mask][v], dp[mask^(1<<i)][v] + dp[(1<<i)][v]);
        
        set<pll> st;
        for(int i=0; i<n; i++) if(dp[mask][i] < INF) st.insert({dp[mask][i], i});
        
        while(sz(st))
        {
            auto itr = st.begin();
            ll v, d;
            v = itr -> S; d = itr -> F;
            st.erase(itr);
            if(dp[mask][v] != d) continue;
            
            for(auto P: G1[v])
            {
                ll u, w;
                u = P.F; w = P.S;
                if(w+d >= dp[mask][u]) continue;
                
                dp[mask][u] = w+d;
                st.insert({dp[mask][u], u});
            } 
        }
    }
    
    ll ans = INF;
    ll f = (1<<k)-1;
    
    for(int i=0; i<n; i++) ans = min(ans, dp[f][i]);
    cout << ans << endl;
}
 

 
int main()
{
    //TOF_IO;
    
    ll nTest=1;
    //cin >> nTest;
	
    while(nTest--) solve();
	
    return 0;
}
 
/********************************************************       The line that separates heaven and hell        *******************************************************/
 
// HELL
/*
void InverseofNumber(ll p = M){Numi[0] = Numi[1] = 1; for (ll i = 2; i <= N; i++){Numi[i] = Numi[p % i] * (p - p / i) % p;}}
void InverseofFactorial(ll p = M){factI[0] = factI[1] = 1;for (ll i = 2; i <= N; i++){factI[i] = (Numi[i] * factI[i - 1]) % p;}}
void factorial(ll p = M){fact[0] = 1;for (ll i = 1; i <= N; i++){fact[i] = (fact[i - 1] * i) % p;}}
ll nPr(ll N, ll R, ll p = M){if (N - R < 0 || R < 0) {return 0;}int ans = ((fact[N]) % p * factI[N - R]) % p;return ans;}
ll nCr(ll N, ll R){if (N - R < 0 || R < 0) {return 0;}int ans = ((fact[N] * factI[R]) % M * factI[N - R]) % M;return ans;}
void comb(){ll p = M;InverseofNumber(p);InverseofFactorial(p);factorial(p);}
*/
 
ll POW(ll a, ll b, ll md) {return (!b ? 1 : (b & 1 ? MOD(a * POW(MOD(a * a, md), b / 2, md), md) : MOD(POW(MOD(a * a, md), b / 2, md), md)));}
ll MOD(ll a, ll b){return (a%b + b) % b;}
 
ll LIS(vector<ll>& v){if (v.size() == 0) {return 0;} vector<ll> tail(v.size(), 0); ll length = 1; tail[0] = v[0]; for (int i = 1; i < v.size(); i++) {auto b = tail.begin(), e = tail.begin() + length; auto it = lower_bound(b, e, v[i]); if (it == tail.begin() + length){tail[length++] = v[i];}else{*it = v[i];}} return length;}
 
void YES(bool flag){cout << (flag? "YES\n" : "NO\n");}
void Yes(bool flag){cout << (flag? "Yes\n" : "No\n");}
 
inline ll mod_add(ll a, ll b){ ll res = a + b; return (res >= M? res - M : res); }
inline ll mod_neg(ll a, ll b){ ll res = (abs(a - b) < M? a - b : (a - b) % M); return (res < 0? res + M : res); }
inline ll mod_mlt(ll a, ll b){ return (a * b % M); }

Compilation message

cities.cpp: In function 'll LIS(std::vector<long long int>&)':
cities.cpp:180:133: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<long long int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
  180 | ll LIS(vector<ll>& v){if (v.size() == 0) {return 0;} vector<ll> tail(v.size(), 0); ll length = 1; tail[0] = v[0]; for (int i = 1; i < v.size(); i++) {auto b = tail.begin(), e = tail.begin() + length; auto it = lower_bound(b, e, v[i]); if (it == tail.begin() + length){tail[length++] = v[i];}else{*it = v[i];}} return length;}
      |                                                                                                                                   ~~^~~~~~~~~~
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 7516 KB Output is correct
2 Correct 2 ms 7516 KB Output is correct
3 Correct 2 ms 9564 KB Output is correct
4 Correct 2 ms 15708 KB Output is correct
5 Correct 4 ms 28108 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 701 ms 33360 KB Output is correct
2 Correct 729 ms 33628 KB Output is correct
3 Correct 277 ms 23316 KB Output is correct
4 Correct 124 ms 21692 KB Output is correct
5 Correct 356 ms 30732 KB Output is correct
6 Correct 122 ms 19792 KB Output is correct
7 Correct 5 ms 9820 KB Output is correct
8 Correct 4 ms 7704 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 8 ms 16216 KB Output is correct
2 Correct 8 ms 15964 KB Output is correct
3 Correct 6 ms 15708 KB Output is correct
4 Correct 7 ms 15776 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 1505 ms 41444 KB Output is correct
2 Correct 1520 ms 41960 KB Output is correct
3 Correct 660 ms 31564 KB Output is correct
4 Correct 787 ms 35708 KB Output is correct
5 Correct 239 ms 29880 KB Output is correct
6 Correct 130 ms 30288 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 3178 ms 54076 KB Output is correct
2 Correct 3062 ms 54000 KB Output is correct
3 Correct 3058 ms 54084 KB Output is correct
4 Correct 1392 ms 43876 KB Output is correct
5 Correct 1487 ms 47684 KB Output is correct
6 Correct 353 ms 42736 KB Output is correct
7 Correct 141 ms 42576 KB Output is correct