제출 #874688

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
874688		MinaRagy06	Tourism (JOI23_tourism)	C++17	100 / 100	3537 ms	101868 KiB

tourism

#include <bits/stdc++.h>
#pragma GCC optimize("Ofast")
using namespace std;
#define ll long long
#define md ((l + r) >> 1)

int lazy[1 << 18];
void add(int i, int l, int r, int s, int e, int v) {
	if (s <= l && r <= e) {
		lazy[i] += v;
		return;
	}
	if (r < s || e < l) {
		return;
	}
	add(i << 1, l, md, s, e, v);
	add(i << 1 | 1, md + 1, r, s, e, v);
}
int get(int i, int l, int r, int x) {
	if (l == r) {
		return lazy[i];
	}
	if (x <= md) {
		return get(i << 1, l, md, x) + lazy[i];
	} else {
		return get(i << 1 | 1, md + 1, r, x) + lazy[i];
	}
}
const int N = 100'005;
int anc[18][N], h[N], mp[N], mph[N], mxh[N], height;
vector<int> adj[N];
int nodes = 1;
void dfs(int i, int d, int x, int curd, int p, int realp) {
	h[x] = d;
	mxh[x] = max(mxh[x], curd);
	mp[i] = x;
	mph[i] = curd;
	height = max(height, d);
	if (curd == 0) {
		anc[0][x] = p;
		for (int j = 1; j < 18; j++) {
			anc[j][x] = anc[j - 1][anc[j - 1][x]];
		}
	}
	for (auto nxt : adj[i]) {
		if (nxt == realp) continue;
		if ((int)adj[i].size() > (2 - (i == 1))) {
			dfs(nxt, d + 1, ++nodes, 0, x, i);
		} else {
			dfs(nxt, d, x, curd + 1, p, i);
		}
	}
}
int sparse[18][N];
int getlca(int u, int v) {
	if (h[u] > h[v]) {
		swap(u, v);
	}
	if (v == 0) return u;
	if (h[u] != h[v]) {
		for (int j = 17; j >= 0; j--) {
			if (h[anc[j][v]] > h[u]) {
				v = anc[j][v];
			}
		}
		v = anc[0][v];
	}
	if (u != v) {
		for (int j = 17; j >= 0; j--) {
			if (anc[j][u] != anc[j][v]) {
				u = anc[j][u];
				v = anc[j][v];
			}
		}
		u = anc[0][u];
	}
	return u;
}
int query(int l, int r) {
	int lg = __lg(r - l + 1);
	return getlca(sparse[lg][l], sparse[lg][r - (1 << lg) + 1]);
}
stack<array<int, 2>> s[N];
int main() {
	ios_base::sync_with_stdio(0), cin.tie(0);
	int n, m, q;
	cin >> n >> m >> q;
	for (int i = 1, u, v; i < n; i++) {
		cin >> u >> v;
		adj[u].push_back(v);
		adj[v].push_back(u);
	}
	dfs(1, 0, 1, 0, 1, 1);
	int arr[m];
	for (int i = 0; i < m; i++) {
		cin >> arr[i];
	}
	for (int i = 0; i < m; i++) {
		sparse[0][i] = mp[arr[i]];
	}
	for (int j = 1; j < 18; j++) {
		for (int i = 0; i + (1 << (j - 1)) < m; i++) {
			sparse[j][i] = getlca(sparse[j - 1][i], sparse[j - 1][i + (1 << (j - 1))]);
		}
	}
	vector<array<int, 3>> ask[m];
	for (int i = 0; i < q; i++) {
		int l, r;
		cin >> l >> r;
		l--, r--;
		int lca = query(l, r);
		ask[r].push_back({l, i, h[lca]});
	}
	int ans[q]{};
	array<int, 2> a[m];
	for (int i = 0; i < m; i++) {
		a[i][0] = mp[arr[i]];
		a[i][1] = mph[arr[i]];
	}
	for (int j = height; j >= 0; j--) {
		memset(lazy, 0, sizeof lazy);
		for (int i = 0; i <= n; i++) {
			while (s[i].size()) s[i].pop();
			s[i].push({(int)1e9, -1});
		}
		for (int r = 0; r < m; r++) {
			auto &[cura, curh] = a[r];
			if (j > h[cura]) goto askl;
			add(1, 0, m - 1, s[cura].top()[1] + 1, r, curh + 1);
			while (curh >= s[cura].top()[0]) {
				array<int, 2> lst = s[cura].top();
				s[cura].pop();
				add(1, 0, m - 1, s[cura].top()[1] + 1, lst[1], curh - lst[0]);
			}
			s[cura].push({curh, r});
			cura = anc[0][cura];
			curh = mxh[cura];
askl:
			for (auto &[l, idx, mnh] : ask[r]) {
				if (j < mnh) continue;
				int v = get(1, 0, m - 1, l);
				ans[idx] += v;
			}
		}
	}
	for (int i = 0; i < m; i++) {
		a[i][0] = mp[arr[i]];
		a[i][1] = mph[arr[i]];
	}
	for (int j = height; j >= 0; j--) {
		memset(lazy, 0, sizeof lazy);
		for (int i = 0; i <= n; i++) {
			while (s[i].size()) s[i].pop();
			s[i].push({(int)-1e9, -1});
		}
		for (int r = 0; r < m; r++) {
			auto &[cura, curh] = a[r];
			if (j > h[cura]) goto askl2;
			add(1, 0, m - 1, s[cura].top()[1] + 1, r, curh);
			while (curh <= s[cura].top()[0]) {
				array<int, 2> lst = s[cura].top();
				s[cura].pop();
				add(1, 0, m - 1, s[cura].top()[1] + 1, lst[1], curh - lst[0]);
			}
			s[cura].push({curh, r});
			cura = anc[0][cura];
			curh = mxh[cura];
askl2:
			for (auto &[l, idx, mnh] : ask[r]) {
				if (j != mnh) continue;
				int v = get(1, 0, m - 1, l);
				ans[idx] -= v;
			}
		}
	}
	for (auto i : ans) {
		cout << i << '\n';
	}
	return 0;
}

• Subtask 1: 5 / 5
• Subtask 2: 5 / 5
• Subtask 3: 7 / 7
• Subtask 4: 18 / 18
• Subtask 5: 24 / 24
• Subtask 6: 41 / 41