이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <iostream>
using namespace std;
typedef long long ll;
typedef pair<int, int> ii;
typedef vector<ii> vii;
typedef vector<int> vi;
#define INF 2000000000
#define MOD 1000000007
#define loop(x,n) for(int x = 0; x < n; ++x)
#define iloop(x,a,n) for(int x=a; x<n; ++x)
#define sloop(e,s) for(auto&& e : s)
#define itloop(it,m) for(auto&& it = m.begin(); it!=m.end(); ++it)
#define F first
#define S second
#define PB push_back
#define MP make_pair
// num_paid (inc. current), left_to_pay; num=-1 if impossible
ii DP[1<<20];
int main() {
// ii DP[1<<2];
// freopen("bank.in","r",stdin);
ios::sync_with_stdio(false);
cin.tie(nullptr);
int N,M;
cin >> N >> M;
int salaries[N], notes[M];
loop(i,N) {
cin >> salaries[i];
}
loop(i,M) {
cin >> notes[i];
}
bool solved = false;
loop(bm,1<<M) {
bool works = false;
if (!bm) {
DP[bm] = MP(0,salaries[0]);
continue;
}
loop(ind,M) {
if (bm&1<<ind) {
int prev = bm^1<<ind;
if (DP[prev].S==0) {
if (salaries[DP[prev].F+1]>=notes[ind]) {
DP[bm] = MP(DP[prev].F+1,salaries[DP[prev].F+1]-notes[ind]);
works = true;
}
} else if (DP[prev].F>=0 && notes[ind]<=DP[prev].S) {
DP[bm] = MP(DP[prev].F,DP[prev].S-notes[ind]);
works = true;
}
}
if (works) break;
}
if (!works) {
DP[bm] = MP(-1,-1);
}
if (DP[bm] == MP(N-1,0)) {
solved = true;
cout << "YES";
break;
}
}
if (!solved) cout << "NO";
}
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