이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
using namespace std ;
#include <bits/stdc++.h> /* #7th-Polygon */
typedef pair < int , int > IntInt ;
const int N = 1e5 + 7 ;
const int K = 1e2 + 7 ;
const int INF = 1e9 + 7 ;
int n , k ;
unsigned int a[N] , dp[N][K] ;
int main()
{
ios::sync_with_stdio(false) ;
cout.tie(nullptr) ;
cin.tie(nullptr) ;
cin >> n >> k ;
for (int i = 1 ; i <= n ; ++i)
cin >> a[i] ;
memset(dp , -1 , sizeof(dp)) ;
dp[0][1] = 0 ;
for (int i = 1 ; i <= n ; ++i)
dp[i][1] = max(dp[i - 1][1] , a[i]) ;
for (int b = 2 ; b <= k ; ++b)
{
stack < IntInt > my_stack ;
for (int i = b ; i <= n ; ++i)
{
int min_dp = dp[i - 1][b - 1] ;
for ( ; my_stack.size() ; my_stack.pop())
{
if (a[my_stack.top().first] > a[i]) break ;
min_dp = min(min_dp , my_stack.top().second) ;
}
dp[i][b] = min_dp + a[i] ;
if (my_stack.size() && dp[i][b] > dp[i][my_stack.top().first])
dp[i][b] = dp[i][my_stack.top().first] ;
my_stack.emplace(i , min_dp) ;
}
}
for (int b = 1 ; b <= k ; ++b , cerr << "\n")
for (int i = 1 ; i <= n ; ++i)
cerr << dp[i][b] << " " ;
cout << dp[n][k] << "\n" ;
return 0 ;
}
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