Submission #872437

#	Time	Username	Problem	Language	Result	Execution time	Memory
872437		KiaRez	Money (IZhO17_money)	C++17	100 / 100	796 ms	62268 KiB

money

/*
    IN THE NAME OF GOD
*/
#include <bits/stdc++.h>

// #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
// #pragma GCC optimize("O3")
// #pragma GCC optimize("unroll-loops")

using namespace std;

typedef long long ll;
typedef pair<ll, ll> pll;
typedef pair<int, int> pii;
typedef long double ld;

#define F                                      first
#define S                                      second
#define Mp                                     make_pair
#define pb                                     push_back
#define pf                                     push_front
#define size(x)                                ((ll)x.size())
#define all(x)                                 (x).begin(),(x).end()
#define kill(x)		                           cout << x << '\n', exit(0);
#define fuck(x)                                cout << "(" << #x << " , " << x << ")" << endl
#define endl                                   '\n'

const int N = 1e6+23, lg = 20;
ll Mod = 1e9+7; //998244353;

inline ll MOD(ll a, ll mod=Mod) {a%=mod; (a<0)&&(a+=mod); return a;}
inline ll poww(ll a, ll b, ll mod=Mod) {
    ll ans = 1;
    a=MOD(a, mod);
    while (b) {
        if (b & 1) ans = MOD(ans*a, mod);
        b >>= 1;
        a = MOD(a*a, mod);
    }
    return ans;
}

int n, a[N], dp[N], ptr=1;
set<pii> st;
int main () {
	ios_base::sync_with_stdio(false), cin.tie(0);

	cin>>n;
	for(int i=1; i<=n; i++) {
		cin>>a[i];
	}

	dp[1] = 1;
	for(int i=2; i<=n; i++) {
		if(a[i] < a[i-1]) {
			while(ptr<i) {
				st.insert({a[ptr], ptr});
				ptr++;
			}
			dp[i] = dp[i-1] + 1;
			continue;
		}
		while(ptr < i) {
			auto it = st.lower_bound(Mp(a[ptr], n+1));
			if(it==st.end() || (*it).F >= a[i]) {
				int x = 0;
				if(size(st)==0 || it==st.begin()) x = 1;
				else {
					it--;
					if((*it).F <= a[ptr]) x=1;
				}
				if(x==1) break;
			}
			st.insert(Mp(a[ptr], ptr));
			ptr++;
		}
		dp[i] = dp[ptr-1] + 1;
	}

	cout<<dp[n]<<endl;

	return 0;
}

• Subtask 1: 9 / 9
• Subtask 2: 16 / 16
• Subtask 3: 20 / 20
• Subtask 4: 55 / 55