이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
# include <stdio.h>
# include <bits/stdc++.h>
#define _USE_MATH_DEFINES_
#define ll long long
#define ld long double
#define Accepted 0
#define pb push_back
#define mp make_pair
#define sz(x) (int)(x.size())
#define every(x) x.begin(),x.end()
#define F first
#define S second
#define For(i,x,y) for (int i = x; i <= y; ++i)
#define FOr(i,x,y) for (int i = x; i >= y; --i)
#define SpeedForce ios_base::sync_with_stdio(0), cin.tie(0)
// ROAD to... Red
using namespace std;
inline bool isvowel (char c) {
c = tolower(c);
if (c == 'a' || c == 'e' || c == 'i' || c == 'y' || c == 'o' || c == 'u') return 1;
return 0;
}
const double eps = 0.000001;
const ld pi = acos(-1);
const int maxn = 1e7 + 9;
const int mod = 1e9 + 7;
const ll MOD = 1e18 + 9;
const ll INF = 1e18 + 123;
const int inf = 2e9 + 11;
const int mxn = 1e6 + 9;
const int N = 1e5 + 123;
const int M = 22;
const int pri = 997;
const int Magic = 2101;
const int dx[] = {-1, 0, 1, 0};
const int dy[] = {0, -1, 0, 1};
int n;
int a[N];
int b[N];
int v[N];
int p[N];
pair < int, int > dp[12][(1 << 10) + 12][(1 << 10) + 12];
int main () {
SpeedForce;
cin >> n;
For (i, 1, n) cin >> a[i];
For (i, 1, n) cin >> b[i];
For (i, 1, n) {
v[i] = 1;
int j = 0, x = (a[i] >> 10);
for (int mask = 0; mask < (1 << 10); ++mask) {
int B = b[i] - __builtin_popcount(x & mask);
if (B >= 0 && B <= 10) {
int y = (a[i] & ((1 << 10) - 1));
if (dp[B][mask][y].F + 1 > v[i]) {
v[i] = dp[B][mask][y].F + 1;
j = dp[B][mask][y].S;
}
}
}
p[i] = j;
for (int mask = 0; mask < (1 << 10); ++mask) {
int nmask = __builtin_popcount(mask & a[i]);
if (v[i] > dp[nmask][x][mask].F) {
dp[nmask][x][mask] = mp(v[i], i);
}
}
}
int res = max_element(v + 1, v + n + 1) - v;
vector < int > ans;
while (res != 0) {
ans.pb(res);
res = p[res];
}
reverse(every(ans));
cout << ans.size() << '\n';
for (auto it : ans)
cout << it << ' ';
return Accepted;
}
// Coded By OB
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