# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
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871179 | 2023-11-10T08:01:13 Z | Lib | 드문 곤충 (IOI22_insects) | C++17 | 0 ms | 344 KB |
#include <bits/stdc++.h> #include "insects.h" //#include "stub.cpp" using namespace std; deque <int> PrevIndex; int InMachine[2003]; int Permutation[2003]; //saving the answer of each iteration so that we won't accidentially binsearch something we've already calculated int ok[2003]; int n; int TypeCount; int CurrentInMachine; int l,r,mid; int PossibleMincount(int cnt){ PrevIndex.clear(); if(ok[cnt]){ return 1; } //Pushing insects inside the machine, keeping track of the ones being putted inside for this iteration of binary searching for(int i=0;i<n;i++){ if(!InMachine[Permutation[i]]){ InMachine[Permutation[i]]=1; move_inside(Permutation[i]); PrevIndex.push_back(Permutation[i]); if(press_button()>cnt){ move_outside(Permutation[i]); InMachine[Permutation[i]]=0; PrevIndex.pop_back(); } } } if(PrevIndex.size()!=(cnt-l)*TypeCount){ //There clearly exist a type of insect with cardinality less than cnt, so the answer is less than cnt. Removing insects from last iteration. while(!PrevIndex.empty()){ InMachine[PrevIndex.front()]=0; move_outside(PrevIndex.front()); PrevIndex.pop_front(); } PrevIndex.clear(); return 0; }else{ //As every type of insects has at least cnt insects, the answer is at least cnt. Just return true PrevIndex.clear(); for(int i=1;i<=cnt;i++){ ok[i]=1; } return 1; } } int min_cardinality(int N){ n=N; //Create a random permutation to fuck with shitty tests and achieve better query efficiency for(int i=0;i<N;i++){ Permutation[i]=i; } srand(time(NULL)); int Tempval; for(int i=N-1;i>0;i--){ Tempval=rand()%i; swap(Permutation[i],Permutation[Tempval]); } //Remember to initialize as this is multitest for(int i=0;i<N;i++){ InMachine[Permutation[i]]=0; ok[i+1]=0; } PrevIndex.clear(); //Phase 1: Determining the amount of different types of insects for(int i=0;i<n;i++){ move_inside(Permutation[i]); InMachine[Permutation[i]]=1; PrevIndex.push_back(Permutation[i]); if(press_button()>1){ move_outside(Permutation[i]); InMachine[Permutation[i]]=0; PrevIndex.pop_back(); } } TypeCount=PrevIndex.size(); r=(N/TypeCount); l=1; //Phase 2: Binary search for the answer while(r-l>1){ mid=(l+r)/2; if(PossibleMincount(mid)){ l=mid; }else{ r=mid-1; } } for(int i=N/TypeCount;i>=1;i--){ if(ok[i]){ return i; } } }
Compilation message
# | 결과 | 실행 시간 | 메모리 | Grader output |
---|---|---|---|---|
1 | Incorrect | 0 ms | 344 KB | Wrong answer. |
2 | Halted | 0 ms | 0 KB | - |
# | 결과 | 실행 시간 | 메모리 | Grader output |
---|---|---|---|---|
1 | Incorrect | 0 ms | 344 KB | Wrong answer. |
2 | Halted | 0 ms | 0 KB | - |
# | 결과 | 실행 시간 | 메모리 | Grader output |
---|---|---|---|---|
1 | Incorrect | 0 ms | 344 KB | Wrong answer. |
2 | Halted | 0 ms | 0 KB | - |