Submission #870871

#TimeUsernameProblemLanguageResultExecution timeMemory
870871epicci23Sjekira (COCI20_sjekira)C++17
110 / 110
65 ms19648 KiB
#include "bits/stdc++.h" using namespace std; #define pb push_back #define endl "\n" #define int long long #define sz(x) ((int)(x).size()) #define all(x) (x).begin(),(x).end() /* stuff you should look for * int overflow, array bounds * special cases (n=1?) * do smth instead of nothing and stay organized * WRITE STUFF DOWN * DON'T GET STUCK ON ONE APPROACH * SIMPLIFY THE PROBLEM * READ THE STATEMENT CAREFULLY !!! if there is an specified/interesting smth(i.e. constraint) in the statement, then you must be careful about that */ const int N = 1e5 + 5; int ar[N],par[N],ans=0; vector<int> v[N],v2[N],vis(N,0); int find(int a){ if(par[a]==a) return a; return par[a]=find(par[a]); } void unite(int a,int b){ a=find(a),b=find(b); if(ar[a]>ar[b]) swap(a,b); par[a]=b; } void dfs(int c,int p){ ans += sz(v2[c]) * ar[c]; for(int x:v2[c]){ if(x==p) continue; dfs(x,c); } } void solve(){ iota(par,par+N,0LL); int n; cin >> n; for(int i=1;i<=n;i++) cin >> ar[i]; for(int i=1;i<n;i++){ int a,b; cin >> a >> b; v[a].pb(b); v[b].pb(a); } vector<array<int,2>> xd; for(int i=1;i<=n;i++) xd.pb({ar[i],i}); sort(all(xd)); for(auto x:xd){ int a = x[1]; vis[a] = 1; for(int u : v[a]){ if(!vis[u]) continue; v2[a].pb(find(u)); v2[find(u)].pb(a); unite(a,u); } } dfs(1,0); cout << ans << endl; } int32_t main(){ cin.tie(0); ios::sync_with_stdio(0); int t=1;//cin >> t; while(t--) solve(); return 0; }
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