oj.uz

답안 #870077

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
870077 2023-11-06T21:36:29 Z tvladm2009 Tents (JOI18_tents) C++17
100 / 100
 242 ms 32180 KB 
#include <bits/stdc++.h>

using i64 = long long;

template<class T>
constexpr T power(T a, i64 b) {
    T res = 1;
    for (; b; b /= 2, a *= a) {
        if (b % 2) {
            res *= a;
        }
    }
    return res;
}

constexpr i64 mul(i64 a, i64 b, i64 p) {
    i64 res = a * b - i64(1.L * a * b / p) * p;
    res %= p;
    if (res < 0) {
        res += p;
    }
    return res;
}
template<i64 P>
struct MLong {
    i64 x;
    constexpr MLong() : x{} {}
    constexpr MLong(i64 x) : x{norm(x % getMod())} {}

    static i64 Mod;
    constexpr static i64 getMod() {
        if (P > 0) {
            return P;
        } else {
            return Mod;
        }
    }
    constexpr static void setMod(i64 Mod_) {
        Mod = Mod_;
    }
    constexpr i64 norm(i64 x) const {
        if (x < 0) {
            x += getMod();
        }
        if (x >= getMod()) {
            x -= getMod();
        }
        return x;
    }
    constexpr i64 val() const {
        return x;
    }
    explicit constexpr operator i64() const {
        return x;
    }
    constexpr MLong operator-() const {
        MLong res;
        res.x = norm(getMod() - x);
        return res;
    }
    constexpr MLong inv() const {
        assert(x != 0);
        return power(*this, getMod() - 2);
    }
    constexpr MLong &operator*=(MLong rhs) & {
        x = mul(x, rhs.x, getMod());
        return *this;
    }
    constexpr MLong &operator+=(MLong rhs) & {
        x = norm(x + rhs.x);
        return *this;
    }
    constexpr MLong &operator-=(MLong rhs) & {
        x = norm(x - rhs.x);
        return *this;
    }
    constexpr MLong &operator/=(MLong rhs) & {
        return *this *= rhs.inv();
    }
    friend constexpr MLong operator*(MLong lhs, MLong rhs) {
        MLong res = lhs;
        res *= rhs;
        return res;
    }
    friend constexpr MLong operator+(MLong lhs, MLong rhs) {
        MLong res = lhs;
        res += rhs;
        return res;
    }
    friend constexpr MLong operator-(MLong lhs, MLong rhs) {
        MLong res = lhs;
        res -= rhs;
        return res;
    }
    friend constexpr MLong operator/(MLong lhs, MLong rhs) {
        MLong res = lhs;
        res /= rhs;
        return res;
    }
    friend constexpr std::istream &operator>>(std::istream &is, MLong &a) {
        i64 v;
        is >> v;
        a = MLong(v);
        return is;
    }
    friend constexpr std::ostream &operator<<(std::ostream &os, const MLong &a) {
        return os << a.val();
    }
    friend constexpr bool operator==(MLong lhs, MLong rhs) {
        return lhs.val() == rhs.val();
    }
    friend constexpr bool operator!=(MLong lhs, MLong rhs) {
        return lhs.val() != rhs.val();
    }
};

template<>
i64 MLong<0LL>::Mod = 1;

template<int P>
struct MInt {
    int x;
    constexpr MInt() : x{} {}
    constexpr MInt(i64 x) : x{norm(x % getMod())} {}

    static int Mod;
    constexpr static int getMod() {
        if (P > 0) {
            return P;
        } else {
            return Mod;
        }
    }
    constexpr static void setMod(int Mod_) {
        Mod = Mod_;
    }
    constexpr int norm(int x) const {
        if (x < 0) {
            x += getMod();
        }
        if (x >= getMod()) {
            x -= getMod();
        }
        return x;
    }
    constexpr int val() const {
        return x;
    }
    explicit constexpr operator int() const {
        return x;
    }
    constexpr MInt operator-() const {
        MInt res;
        res.x = norm(getMod() - x);
        return res;
    }
    constexpr MInt inv() const {
        assert(x != 0);
        return power(*this, getMod() - 2);
    }
    constexpr MInt &operator*=(MInt rhs) & {
        x = 1LL * x * rhs.x % getMod();
        return *this;
    }
    constexpr MInt &operator+=(MInt rhs) & {
        x = norm(x + rhs.x);
        return *this;
    }
    constexpr MInt &operator-=(MInt rhs) & {
        x = norm(x - rhs.x);
        return *this;
    }
    constexpr MInt &operator/=(MInt rhs) & {
        return *this *= rhs.inv();
    }
    friend constexpr MInt operator*(MInt lhs, MInt rhs) {
        MInt res = lhs;
        res *= rhs;
        return res;
    }
    friend constexpr MInt operator+(MInt lhs, MInt rhs) {
        MInt res = lhs;
        res += rhs;
        return res;
    }
    friend constexpr MInt operator-(MInt lhs, MInt rhs) {
        MInt res = lhs;
        res -= rhs;
        return res;
    }
    friend constexpr MInt operator/(MInt lhs, MInt rhs) {
        MInt res = lhs;
        res /= rhs;
        return res;
    }
    friend constexpr std::istream &operator>>(std::istream &is, MInt &a) {
        i64 v;
        is >> v;
        a = MInt(v);
        return is;
    }
    friend constexpr std::ostream &operator<<(std::ostream &os, const MInt &a) {
        return os << a.val();
    }
    friend constexpr bool operator==(MInt lhs, MInt rhs) {
        return lhs.val() == rhs.val();
    }
    friend constexpr bool operator!=(MInt lhs, MInt rhs) {
        return lhs.val() != rhs.val();
    }
};

template<>
int MInt<0>::Mod = 1000000007;

template<int V, int P>
constexpr MInt<P> CInv = MInt<P>(V).inv();

constexpr int P = 1000000007;
using Z = MInt<P>;

constexpr int N = 3005;

Z dp[N][N];

Z solve(int x, int y) {
    if (x < 0 || y < 0) {
        return 0;
    } else if (x == 0 || y == 0) {
        return 1;
    } else if (dp[x][y] != 0) {
        return dp[x][y];
    }
    dp[x][y] = solve(x - 1, y) + solve(x - 1, y - 1) * y * 4 + solve(x - 1, y - 2) * (y * (y - 1) / 2) + solve(x - 2, y - 1) * y * (x - 1);
    return dp[x][y];
}

int main() {
    std::ios::sync_with_stdio(false);
    std::cin.tie(nullptr);

    int h, w;
    std::cin >> h >> w;
    std::cout << solve(h, w) - 1 << "\n";
    return 0;
}

Subtask #1
48.0 / 48.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 348 KB Output is correct
2 Correct 0 ms 348 KB Output is correct
3 Correct 0 ms 604 KB Output is correct
4 Correct 1 ms 1116 KB Output is correct
5 Correct 1 ms 604 KB Output is correct
6 Correct 1 ms 1372 KB Output is correct
7 Correct 1 ms 856 KB Output is correct
8 Correct 1 ms 1372 KB Output is correct
9 Correct 1 ms 860 KB Output is correct
10 Correct 2 ms 1628 KB Output is correct
11 Correct 0 ms 468 KB Output is correct
12 Correct 3 ms 1880 KB Output is correct

Subtask #2
52.0 / 52.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 348 KB Output is correct
2 Correct 0 ms 348 KB Output is correct
3 Correct 0 ms 604 KB Output is correct
4 Correct 1 ms 1116 KB Output is correct
5 Correct 1 ms 604 KB Output is correct
6 Correct 1 ms 1372 KB Output is correct
7 Correct 1 ms 856 KB Output is correct
8 Correct 1 ms 1372 KB Output is correct
9 Correct 1 ms 860 KB Output is correct
10 Correct 2 ms 1628 KB Output is correct
11 Correct 0 ms 468 KB Output is correct
12 Correct 3 ms 1880 KB Output is correct
13 Correct 0 ms 348 KB Output is correct
14 Correct 5 ms 9964 KB Output is correct
15 Correct 165 ms 29220 KB Output is correct
16 Correct 2 ms 1368 KB Output is correct
17 Correct 14 ms 5024 KB Output is correct
18 Correct 33 ms 9276 KB Output is correct
19 Correct 236 ms 31256 KB Output is correct
20 Correct 146 ms 25480 KB Output is correct
21 Correct 79 ms 16044 KB Output is correct
22 Correct 93 ms 20052 KB Output is correct
23 Correct 77 ms 19712 KB Output is correct
24 Correct 242 ms 32180 KB Output is correct
25 Correct 199 ms 27156 KB Output is correct
26 Correct 210 ms 29852 KB Output is correct
27 Correct 232 ms 31056 KB Output is correct