제출 #868390

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
868390		smirichto	Cloud Computing (CEOI18_clo)	C++17	54 / 100	574 ms	2448 KiB

clo

#include<bits/stdc++.h>

using namespace std;
typedef long long ll;
typedef long double ld;
#define pb push_back
#define pi pair<ll,ll>
#define F first
#define S second
#define all(x) (x).begin(), (x).end()
#define alll(x) ((x).begin()+1), (x).end()
#define clean(v) (v).resize(distance((v).begin(), unique(all(v))));
#define yes cout<<"Yes"<<endl;
#define no cout<<"No"<<endl;
#define mod mod
#define endl '\n'
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const ll mod = 998244353;

void io() {
    ios::sync_with_stdio(false);
    cin.tie(NULL);
}

template<class T>
bool ckmax(T &a, const T &b) { return a < b ? a = b, 1 : 0; }

template<class T>
bool ckmin(T &a, const T &b) { return a > b ? a = b, 1 : 0; }

void nop() {
    cout << -1 << endl;
    return;
}

const ll N = 1e5+5 ;
array<ll,4> tab[N] ;

void solve() {
    ll n; cin>>n ;
    for(ll i = 1 ; i<=n ; i++){
        cin>>tab[i][1]>>tab[i][0]>>tab[i][2] ;
        tab[i][3] = 1 ;
    }
    ll m ; cin>>m ;
    for(ll j = 1 ; j<=m ; j++){
        ll i = j + n ;
        cin>>tab[i][1]>>tab[i][0]>>tab[i][2] ;
    }

    vector<ll> dp(n * 55 , -1e17) ;
    sort(tab+1 , tab+1+n+m) ;
    reverse(tab+1 , tab+1+n+m) ;

    dp[0] = 0 ;
    for(ll i = 1 ; i<=n + m ; i++){
        vector<ll> ndp(n * 55 , -1e17) ;
        if(tab[i][3]){
            for(ll j = 0 ; j<=n * 50 ; j++){
                ckmax(ndp[j] , dp[j]) ;
                if(j + tab[i][1] <= n * 50) ckmax(ndp[j + tab[i][1]] , dp[j] - tab[i][2]) ;
            }
        }
        else{
            for(ll j = 0 ; j<=n * 50 ; j++){
                ckmax(ndp[j] , dp[j]) ;
                if(j>=tab[i][1]){
                    ckmax(ndp[j - tab[i][1]] , dp[j] + tab[i][2]) ;
                }
            }
        }
        dp.swap(ndp) ;
    }
    ll ans = 0 ;
    for(ll i = 0 ; i<=n*50 ; i++) ckmax(ans , dp[i]) ;
    cout<<ans<<endl;

}

int main() {

    io();
    ll tt = 1;
    //cin>>tt ;
    while (tt--) {
        solve();
    }

    return 0;
}

• Subtask 1: 18 / 18
• Subtask 2: 0 / 18
• Subtask 3: 18 / 18
• Subtask 4: 0 / 18
• Subtask 5: 18 / 18
• Subtask 6: 0 / 10