이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
template <class S, S (*f)(S, S), S e>
struct PST {
struct T {
T *l, *r; S s;
T() : s() {l = r = nullptr;}
T(const S &v) : s(v) {l = r = nullptr;}
T(T *t) : l(t->l), r(t->r), s(t->s) {}
T(T *a, T *b) : l(a), r(b), s() {
if (l) s = f(s, l->s);
if (r) s = f(s, r->s);
}
};
int n;
vector<T*> rts;
PST(int m) : PST(vector<S>(m, e)) {
}
PST(const vector<S> &a) : n(a.size()) {
function<T*(int, int)> bld = [&](int l, int r) {
if (l + 1 == r) {
return new T(a[l]);
}
int m = (l + r) / 2;
return new T(bld(l, m), bld(m, r));
};
rts.push_back(bld(0, n));
}
T* set(T *i, int l, int r, int p, const S &v) {
if (l + 1 == r) {
return new T(v);
}
int m = (l + r) / 2;
if (p < m) {
return new T(set(i->l, l, m, p, v), i->r);
} else {
return new T(i->l, set(i->r, m, r, p, v));
}
}
T* upd(T *i, int l, int r, int p, S (*&g)(S a, S b), const S &v) {
if (l + 1 == r) {
return new T(g(i->s, v));
}
int m = (l + r) / 2;
if (p < m) {
return new T(upd(i->l, l, m, p, g, v), i->r);
} else {
return new T(i->l, upd(i->r, m, r, p, g, v));
}
}
S qry(T *i, int l, int r, int L, int R) {
if (R <= l || r <= L) {
return e;
}
if (L <= l && r <= R) {
return i->s;
}
int m = (l + r) / 2;
return f(qry(i->l, l, m, L, R), qry(i->r, m, r, L, R));
}
int lst() {
return rts.size() - 1;
}
int cpy(int k) {
rts.push_back(new T(rts[k]));
return rts.size() - 1;
}
void set(int k, int i, const S &v) {
rts[k] = set(rts[k], 0, n, i, v);
}
void upd(int k, int i, S (*g)(S a, S b), const S &v) {
rts[k] = upd(rts[k], 0, n, i, g, v);
}
void upd(int k, int i, const S &v) {
upd(k, i, f, v);
}
S qry(int k, int l, int r) {
return qry(rts[k], 0, n, l, r);
}
};
ll F(ll x, ll y) {
return x + y;
}
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
int N, M, Q;
cin >> N >> M >> Q;
vector<pair<int, int>> edges(N - 1);
vector<vector<int>> adj(N);
for (int i = 0; i < N - 1; i++) {
int x, y;
cin >> x >> y;
x--, y--;
edges[i] = {x, y};
adj[x].push_back(i);
adj[y].push_back(i);
}
vector<pair<int, int>> ch(M);
for (int i = 0; i < M; i++) {
int p, c;
cin >> p >> c;
ch[i] = {c, p - 1};
}
sort(ch.begin(), ch.end());
vector<int> t(N - 1);
{
auto dfs = [&](auto dfs, int x, int p) -> void {
for (int z : adj[x]) {
auto [u, v] = edges[z];
int y = x ^ u ^ v;
if (y != p) {
t[z] = y;
dfs(dfs, y, x);
}
}
};
dfs(dfs, 0, -1);
}
for (int i = 0; i < N; i++) {
for (int &j : adj[i]) {
auto [x, y] = edges[j];
j = i ^ x ^ y;
}
}
vector<int> dep(N), par(N, -1), sz(N);
auto init = [&](auto init, int x) -> void {
if (par[x] != -1) {
adj[x].erase(find(adj[x].begin(), adj[x].end(), par[x]));
}
sz[x] = 1;
for (int &y : adj[x]) {
par[y] = x;
dep[y] = dep[x] + 1;
init(init, y);
sz[x] += sz[y];
if (sz[y] > sz[adj[x][0]]) {
swap(y, adj[x][0]);
}
}
};
init(init, 0);
vector<int> top(N), in(N);
int timer = 0;
auto dfs = [&](auto dfs, int x) -> void {
in[x] = timer++;
for (int y : adj[x]) {
top[y] = adj[x][0] == y ? top[x] : y;
dfs(dfs, y);
}
};
dfs(dfs, 0);
PST<ll, F, 0> q(N);
for (int i = 0; i < M; i++) {
auto [c, p] = ch[i];
q.upd(q.cpy(q.lst()), in[t[p]], c);
for (int j = 0; j < 10; j++) {
q.upd(q.lst(), in[t[p]], 0);
}
}
auto get = [&](int x, int y, int z) {
ll s = 0;
while (top[x] != top[y]) {
if (dep[top[x]] < dep[top[y]]) {
swap(x, y);
}
s += q.qry(z, in[top[x]], in[x] + 1);
x = par[top[x]];
}
if (dep[x] < dep[y]) {
swap(x, y);
}
s += q.qry(z, in[y] + 1, in[x] + 1);
return s;
};
vector<int> S(Q), T(Q), X(Q), a(Q);
vector<ll> Y(Q);
for (int i = 0; i < Q; i++) {
cin >> S[i] >> T[i] >> X[i] >> Y[i];
S[i]--, T[i]--;
int lo = 0, hi = M;
while (lo < hi) {
int mi = (lo + hi + 1) / 2;
if (get(S[i], T[i], mi) <= Y[i]) {
lo = mi;
} else {
hi = mi - 1;
}
}
a[i] = lo;
}
vector<ll> ans(Q);
vector<vector<int>> f(M + 1);
for (int i = 0; i < Q; i++) {
f[a[i]].push_back(i);
}
q = PST<ll, F, 0>(N);
assert(q.lst() == 0);
for (int i = M; i >= 0; i--) {
if (i < M) {
auto [c, p] = ch[i];
q.upd(q.cpy(q.lst()), in[t[p]], 1);
for (int j = 0; j < 10; j++) {
// q.upd(q.lst(), in[t[p]], 0);
}
}
for (int j : f[i]) {
ans[j] = max(-1LL, X[j] - get(S[j], T[j], q.lst()));
}
}
for (int i = 0; i < Q; i++) {
cout << ans[i] << "\n";
}
return 6/22;
}
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