제출 #862023

#제출 시각아이디문제언어결과실행 시간메모리
862023vjudge1Two Currencies (JOI23_currencies)C++17
100 / 100
458 ms67220 KiB
#include <cstring> #include <vector> #include <map> #include <algorithm> #include <iostream> #include <utility> using namespace std; using ll = long long; using ld = long double; #define ShinLena cin.tie(nullptr)->sync_with_stdio(false) #define N 100005 #define M N*40 #define ALL(x) x.begin(), x.end() int A[M], L[M], R[M], ALLOC = 1; ll B[M]; inline int persist1(int a, ll b) { int p = ALLOC++; A[p] = a, B[p] = b; return p; } inline int persist2(int l, int r) { int p = ALLOC++; L[p] = l; R[p] = r; A[p] = A[l] + A[r]; B[p] = B[l] + B[r]; return p; } int build(int l, int r) { if (l == r) return persist1(0, 0); return persist2(build(l, (l+r)/2), build((l+r)/2+1, r)); } int upd(int v, int l, int r, int w, int W) { if (l == r) return persist1(A[v] + 1, B[v] + w); if (W <= (l+r)/2) return persist2(upd(L[v], l, (l+r)/2, w, W), R[v]); return persist2(L[v], upd(R[v], (l+r)/2+1, r, w, W)); } int cord[N], ne, n, m, q, P[N], J[N], D[N], root[N]; vector<int> mark[N]; vector<pair<int, int>> g[N]; ll qry(int u, int v, int a, int l, int r, ll k) { if (l == r) return min(k, B[u] + B[v] - B[a]*2) / cord[l]; ll left = B[L[u]] + B[L[v]] - B[L[a]]*2; if (k < left) return qry(L[u], L[v], L[a], l, (l+r)/2, k); return (A[L[u]]+ A[L[v]]- 2*A[L[a]]) + qry(R[u], R[v], R[a], (l+r)/2+1, r, k - left); } inline int find(int u, int d) { while (D[u] > d) u = D[J[u]] >= d ? J[u] : P[u]; return u; } inline int lca(int u, int v) { if (D[u] < D[v]) swap(v, u); u = find(u, D[v]); while (u != v) if (J[u] == J[v]) u = P[u], v = P[v]; else u = J[u], v = J[v]; return u; } void dfs(int u, int p, int d) { D[u] = d; P[u] = p; J[u] = (D[p] - D[J[p]] == D[J[p]] - D[J[J[p]]]) ? J[J[p]] : p; for (auto [v, i] : g[u]) { if (v == p) continue; root[v] = root[u]; for (auto w : mark[i]) root[v] = upd(root[v], 0, ne, w, lower_bound(cord, cord+ne, w) - cord); dfs(v, u, d+1); } } int main() { ShinLena; cin >> n >> m >> q; for (int u, v, i = 1; i < n; ++i) cin >> u >> v, g[u].emplace_back(v, i), g[v].emplace_back(u, i); for (int p, c; m--; ) cin >> p >> c, mark[p].push_back(c), cord[ne++] = c; sort(cord, cord+ne), ne = unique(cord, cord+ne) - cord - 1; J[1] = 1; root[1] = build(0, ne); dfs(1, 1, 1); for (ll s, t, gold, silver; q--; ) { cin >> s >> t >> gold >> silver; int ps = root[s], pt = root[t], pa = root[lca(s, t)]; int gone = qry(ps, pt, pa, 0, ne, silver), all = A[ps] + A[pt] - 2*A[pa]; cout << ((all - gone > gold) ? -1 : gold - (all - gone)) << '\n'; } return 0; }
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