이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "coprobber.h"
#include <bits/stdc++.h>
using namespace std;
#pragma GCC optimize("Ofast,inline") // Ofast = O3,fast-math,allow-store-data-races,no-protect-parens
#pragma GCC optimize ("unroll-loops")
#pragma GCC target("bmi,bmi2,lzcnt,popcnt") // bit manipulation
#pragma GCC target("movbe") // byte swap
#pragma GCC target("aes,pclmul,rdrnd") // encryption
#pragma GCC target("avx,avx2,f16c,fma,sse3,ssse3,sse4.1,sse4.2")
typedef long long ll;
#define rep(i, a, b) for (int i = (a); i < int(b); i++)
typedef pair<ll, ll> pll;
typedef pair<int, int> pii;
#define pb push_back
// inline void fast() { ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); }
ll INF = 1e15;
ll mod = 1e9 + 7;
// #define int ll
#define float double
int n;
vector<vector<int>> adj;
int cat = -1;
vector<vector<vector<pii>>> dp;
queue<array<int, 3>> q;
vector<vector<int>> r_edges_left;
void sol(int C, int R, int T)
{
// cerr << C << " " << R << " " << T << "\n";
if (T == 1) {
for (int i : adj[R]) {
r_edges_left[C][i]--;
// cerr << "-- " << C << " " << i << " status : " << r_edges_left[C][i] << "\n";
if (r_edges_left[C][i] == 0 && dp[C][i][0].first == -1) {
q.push({C, i, 0});
}
}
}
else if (T == 0) {
if (dp[C][R][1].first == -1) {
dp[C][R][1].first = 1;
dp[C][R][1].second = C;
q.push({C, R, 1});
}
dp[C][R][0].first = 1;
for (int i : adj[C]) {
if (dp[i][R][1].first == -1) {
dp[i][R][1].first = 1;
dp[i][R][1].second = C;
q.push({i, R, 1});
}
}
}
}
int start(int N, bool A[MAX_N][MAX_N])
{
n = N;
adj.assign(n, {});
rep(i,0,n) {
rep(j,i + 1,n) {
if (A[i][j]) {
adj[i].pb(j);
adj[j].pb(i);
}
}
}
dp.assign(n, vector<vector<pii>>(n, vector<pii>(2, {-1, -1})));
rep(i,0,n) {
q.push({i, i, 0});
q.push({i, i, 1});
dp[i][i][0].first = 1;
dp[i][i][1].first = 1;
}
r_edges_left.assign(n, vector<int>(n, -1));
rep(i,0,n) {
rep(j,0,n) {
r_edges_left[i][j] = adj[j].size();
}
}
while (!q.empty()) {
auto x = q.front();
q.pop();
sol(x[0], x[1], x[2]);
}
// rep(i,0,n) {
// rep(j,0,n) {
// rep(k,0,2) {
// cerr << dp[i][j][k].first << " ";
// }
// cerr << endl;
// }
// cerr << endl;
// }
rep(i,0,n) {
bool w = true;
rep(j,0,n) {
if (dp[i][j][1].first != 1) w = false;
}
if (w) {
return cat = i;
}
}
return -1;
}
int nextMove(int R)
{
if (cat == R) return cat; //
return cat = dp[cat][R][1].second;
}
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