Submission #860883

#	Time	Username	Problem	Language	Result	Execution time	Memory
860883		amine_aroua	Cloud Computing (CEOI18_clo)	C++17	100 / 100	858 ms	2904 KiB

clo

#include <bits/stdc++.h>
//#pragma GCC optimize("O3")
//#pragma GCC optimize("unroll-loops")
using namespace std;
#define int long long
#define vi vector<int>
#define vl vector<long long>
#define vii vector<pair<int,int>>
#define vll vector<pair<long long,long long>>
#define pb push_back
#define ll long long
#define ld long double
#define nl '\n'
#define boost ios::sync_with_stdio(false)
#define mp make_pair
#define se second
#define fi first
#define fore(i, y) for(int i = 0; i < y; i++)
#define forr(i,x,y) for(int i = x;i<=y;i++)
#define forn(i,y,x) for(int i = y; i >= x; i--)
#define all(v) v.begin(),v.end()
#define sz(v) (int)v.size()
#define clr(v,k) memset(v,k,sizeof(v))
#define rall(v) v.rbegin() , v.rend()
#define pii pair<int,int>
#define pll pair<ll , ll>

const ll MOD = 1e9 + 7;
const ll INF = 1e18 + 1;

ll gcd(ll a , ll b) {return b ? gcd(b , a % b) : a ;} // greatest common divisor (gcd)
ll lcm(ll a , ll b) {return a * (b / gcd(a , b));} // least common multiple (lcm)

// HERE IS THE SOLUTION
const int MAXN = 50 * 5000;
signed main()
{
    boost;
    cin.tie(0);
    cout.tie(0);
    int n , m;
    cin>>n;
    vector<tuple<int , int , int>> obj;
    fore(i , n)
    {
        int c , f , v;
        cin>>c>>f>>v;
        obj.pb({f , c , -v});
    }
    cin>>m;
    fore(i , m)
    {
        int c , f , v;
        cin>>c>>f>>v;
        obj.pb({f , -c , v});
    }
    sort(rall(obj));
    vi dp(MAXN , -INF);
    dp[0] = 0;
    for(auto [f , c , v] : obj)
    {
        if(c >= 0)
        {
            forn(i , MAXN - 1, 0)
            {
                if(i - c >= 0)
                {
                    dp[i] = max(dp[i] , dp[i - c] + v);
                }
            }
        }
        else
        {
            fore(i , MAXN)
            {
                if(i - c < MAXN)
                {
                    dp[i] = max(dp[i] , dp[i - c] + v);
                }
            }
        }
    }
    int ans = -INF;
    fore(i , MAXN)
        ans = max(ans , dp[i]);
    cout<<ans<<nl;
}

• Subtask 1: 18 / 18
• Subtask 2: 18 / 18
• Subtask 3: 18 / 18
• Subtask 4: 18 / 18
• Subtask 5: 18 / 18
• Subtask 6: 10 / 10