제출 #860594

#제출 시각아이디문제언어결과실행 시간메모리
860594E869120Event Hopping (BOI22_events)C++14
100 / 100
321 ms26856 KiB
#include <bits/stdc++.h> using namespace std; class RangeMin { public: int size_ = 1; vector<pair<int, int>> dat; void init(int sz) { while (size_ <= sz) size_ *= 2; dat.resize(size_ * 2, make_pair(0, 0)); } void update(int pos, pair<int, int> val) { pos += size_; dat[pos] = val; while (pos >= 2) { pos >>= 1; dat[pos] = min(dat[pos * 2 + 0], dat[pos * 2 + 1]); } } pair<int, int> query_(int l, int r, int a, int b, int u) { if (l <= a && b <= r) return dat[u]; if (r <= a || b <= l) return make_pair(2000000000, -1); pair<int, int> v1 = query_(l, r, a, (a + b) / 2, u * 2 + 0); pair<int, int> v2 = query_(l, r, (a + b) / 2, b, u * 2 + 1); return min(v1, v2); } pair<int, int> query(int l, int r) { return query_(l, r, 0, size_, 1); } }; int N, S[1 << 19], T[1 << 19]; int Q, X[1 << 19], Y[1 << 19]; int Prev[1 << 19][22]; int solve(int stt, int goa) { if (T[stt] > T[goa]) return -1; if (stt == goa) return 0; if (T[stt] >= S[goa]) return 1; // Doubling int cx = goa, cur = 0; for (int d = 21; d >= 0; d--) { int nex = Prev[cx][d]; if (S[nex] > T[stt]) { cx = nex; cur += (1 << d); } } if (cur >= (1 << 21)) return -1; return cur + 2; } int main() { // Step 1. Input cin >> N >> Q; for (int i = 1; i <= N; i++) cin >> S[i] >> T[i]; for (int i = 1; i <= Q; i++) cin >> X[i] >> Y[i]; // Step 2. Sorting vector<tuple<int, int, int>> List; for (int i = 1; i <= N; i++) List.push_back(make_tuple(T[i], S[i], i)); sort(List.begin(), List.end()); RangeMin Z; Z.init(List.size() + 2); for (int i = 0; i < (int)List.size(); i++) { Z.update(i, make_pair(get<1>(List[i]), get<2>(List[i]))); } // Step 3. Get Prev for (int i = 0; i < (int)List.size(); i++) { int idx = get<2>(List[i]); int pos1 = lower_bound(List.begin(), List.end(), make_tuple(S[idx], -1, -1)) - List.begin(); pair<int, int> ret = Z.query(pos1, i); if (ret.first == 2000000000) Prev[idx][0] = idx; else Prev[idx][0] = ret.second; } // Step 4. Doubling for (int d = 1; d <= 21; d++) { for (int i = 1; i <= N; i++) Prev[i][d] = Prev[Prev[i][d - 1]][d - 1]; } // Step 5. Answer Query for (int i = 1; i <= Q; i++) { int ret = solve(X[i], Y[i]); if (ret == -1) cout << "impossible" << endl; else cout << ret << endl; } return 0; }
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