답안 #860451

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
860451 2023-10-13T02:51:34 Z meliodasssf Bajka (COCI20_bajka) C++17
70 / 70
5 ms 1160 KB
#include <bits/stdc++.h>
 
using namespace std;
 
typedef long long ll;
 
const int N_MAX = 302;
const int M_MAX = 302;
 
int n, m;
 
string a, b;
 
ll dp[M_MAX][N_MAX];
 
struct State
{
    int pref;
    int pos;
};
 
struct Path
{
    State s;
    ll len;
};
 
bool operator < (const Path &a, const Path &b)
{
    return a.len > b.len;
}
 
priority_queue <Path> pq;
 
bool visited[M_MAX][N_MAX];
 
int L[N_MAX], R[N_MAX];
 
map <char, int> mp;
 
void Dijkstra ()
{
    for(int i = 1; i <= n; i++)
        if(a[i] == b[1])
            pq.push(Path{State{1, i}, 0});
    while(pq.empty() == false)
    {
        Path p = pq.top();
        pq.pop();
        if(visited[p.s.pref][p.s.pos] == true)
            continue;
        visited[p.s.pref][p.s.pos] = true;
        dp[p.s.pref][p.s.pos] = p.len;
        if(p.s.pref == m)
            continue;
        if(p.s.pos > 1 && a[p.s.pos - 1] == b[p.s.pref + 1] && visited[p.s.pref + 1][p.s.pos - 1] == false)
            pq.push(Path{State{p.s.pref + 1, p.s.pos - 1}, p.len + 1});
        if(p.s.pos < n && a[p.s.pos + 1] == b[p.s.pref + 1] && visited[p.s.pref + 1][p.s.pos + 1] == false)
            pq.push(Path{State{p.s.pref + 1, p.s.pos + 1}, p.len + 1});
        int pos1 = L[p.s.pos];
        int pos2 = R[p.s.pos];
        if(pos1 != 0 && visited[p.s.pref][pos1] == false)
            pq.push(Path{State{p.s.pref, pos1}, p.len + abs(p.s.pos - pos1)});
        if(pos2 != 0 && visited[p.s.pref][pos2] == false)
            pq.push(Path{State{p.s.pref, pos2}, p.len + abs(p.s.pos - pos2)});
    }
}
 
int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);
    cin >> n >> m;
    cin >> a >> b;
    a = " " + a;
    b = " " + b;
    for(int i = 1; i <= n; i++)
    {
        if(mp.find(a[i]) != mp.end())
            L[i] = mp[a[i]];
        mp[a[i]] = i;
    }
    mp.clear();
    for(int i = n; i >= 1; i--)
    {
        if(mp.find(a[i]) != mp.end())
            R[i] = mp[a[i]];
        mp[a[i]] = i;
    }
    mp.clear();
    Dijkstra();
    ll ans = LLONG_MAX;
    for(int i = 1; i <= n; i++)
        if(visited[m][i] == true)
            ans = min(ans, dp[m][i]);
    if(ans == LLONG_MAX)
        ans = -1;
    cout << ans << "\n";
    return 0;
}
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 344 KB Output is correct
2 Correct 1 ms 344 KB Output is correct
3 Correct 0 ms 348 KB Output is correct
4 Correct 1 ms 1116 KB Output is correct
5 Correct 1 ms 1116 KB Output is correct
6 Correct 0 ms 348 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 604 KB Output is correct
2 Correct 1 ms 1116 KB Output is correct
3 Correct 1 ms 1112 KB Output is correct
4 Correct 1 ms 1124 KB Output is correct
5 Correct 0 ms 348 KB Output is correct
6 Correct 0 ms 348 KB Output is correct
7 Correct 2 ms 1116 KB Output is correct
8 Correct 5 ms 1116 KB Output is correct
9 Correct 3 ms 1116 KB Output is correct
10 Correct 0 ms 348 KB Output is correct
11 Correct 2 ms 1160 KB Output is correct