#include <bits/stdc++.h>
//#include "peru.h"
using namespace std;
const int NMAX = 2500000;
const int MOD = 1e9 + 7;
long long dp[NMAX];
int solve( int n, int k, int* v ) {
deque <int> dq;
deque <pair<int, long long>> dq2;
int ans = 0;
for ( int i = 0; i < n; i ++ ) {
while ( !dq.empty() && v[dq.back()] <= v[i] ) dq.pop_back();
dq.push_back( i );
if ( dq.front() <= i - k ) dq.pop_front();
dp[i] = v[dq.front()] + ( i >= k ? dp[i - k] : 0 );
while ( !dq2.empty() && v[dq2.back().first] <= v[i] ) dq2.pop_back();
if ( dq.size() > 1 ) {
long long aux = v[i] + dp[dq[dq.size() - 2]];
while ( !dq2.empty() && dq2.back().second >= aux ) dq2.pop_back();
dq2.push_back( { i, aux } );
if ( dq2.front().first <= i - k ) dq2.pop_front();
if ( dq2.front().first == dq.front() ) dq2.pop_front();
if ( !dq2.empty() ) dp[i] = min( dp[i], dq2.front().second );
}
// cout << i << ": " << endl;
// for ( auto x : dq ) cout << x << ' ';
// cout << endl;
// for ( auto p : dq2 ) cout << "( " << p.first << ", " << p.second << " )" << ' ';
// cout << endl << "and the answer is: ";
// cout << dp[i] << ' ';
// cout << endl;
ans = ( (long long)ans * 23 + dp[i] ) % MOD;
}
// cout << endl;
dq.clear();
dq2.clear();
return ans;
}
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
1 ms |
2392 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
1 ms |
2392 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
1 ms |
2392 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |