제출 #858648

#제출 시각아이디문제언어결과실행 시간메모리
858648resting추월 (IOI23_overtaking)C++17
100 / 100
1434 ms161432 KiB
#include <bits/stdc++.h> using namespace std; #define int long long #define ff first #define ss second set<pair<int, int>> restriction; // if "starts after a", has to "end after b" yk int x, l; void init(int32_t L, int32_t N, std::vector<long long> T, std::vector<int32_t> W, int32_t X, int32_t M, std::vector<int32_t> S) { restriction = {}; x = X; l = L; vector<vector<pair<int, int>>> restrictions(M);// yes vector<pair<int, int>> cur; for (int i = 0; i < N; i++) if (W[i] > X) cur.push_back({ T[i], W[i] - X }); for (int i = 0; i < M-1; i++) { sort(cur.begin(), cur.end()); vector<pair<int, int>> res; const int T = cur.size(); for (int j = 0; j < T; j++) res.push_back({ cur[j].ff + cur[j].ss * (S[i + 1] - S[i]), cur[j].ss }); for (int j = 0; j < T - 1; j++) if (res[j].ff > res[j + 1].ff) res[j + 1].ff = res[j].ff; int p = -1; for (int j = 0; j < T; j++) { if(res[j].ff != p){ if(j + 1 == T || cur[j].ff != cur[j+1].ff){ p = res[j].ff; restrictions[i].push_back({ cur[j].ff+1, res[j].ff }); //start, end } } } swap(res, cur); } for (int i = 0; i < M; i++) { reverse(restrictions[i].begin(), restrictions[i].end()); for(auto x : restrictions[i]){ auto y = restriction.upper_bound({x.second, numeric_limits<long long>::max()}); if(y == restriction.begin()) { if(restriction.size() && y->second <= x.first){ continue; } restriction.insert({x.second, x.first}); continue; } else y = prev(y); int tt = x.first; while(y != restriction.end() && y->first >= x.first){ tt = min(tt, y->second); auto t = y; if(t == restriction.begin()) t= restriction.end(); else t = prev(t); restriction.erase(y); y = t; } x.first = tt; auto z = restriction.upper_bound({x.second, numeric_limits<long long>::max()}); if(z != restriction.end() && z->second <= x.first) continue; restriction.insert({x.second, x.first}); } } set<pair<int,int>> bruh; for(auto &x : restriction) bruh.insert({x.second, x.first}); restriction=bruh; return; } long long arrival_time(long long Y) { auto yes = restriction.upper_bound(make_pair( Y, numeric_limits<long long>::max() )); if(yes == restriction.begin()) yes = restriction.end(); else yes = prev(yes); if (yes != restriction.end()) Y = max(Y, yes->second); return Y + x * l; }
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