| # | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
|---|---|---|---|---|---|---|---|
| 857077 | alicanyaz | Combo (IOI18_combo) | C++14 | 0 ms | 0 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp> // Common file
#include <ext/pb_ds/tree_policy.hpp> // Including tree_order_statistics_node_update
#include <ext/pb_ds/detail/standard_policies.hpp>
#define xc3(x) (x*(x-1)*(x-2)/6)
#define xc2(x) ((x)*((x)-1)/2)
#define abs(x) ((x)>0?(x):-((x)))
#define min(x,y) ((x)>(y)?(y):(x))
//#define debug 1
using namespace std;
using namespace __gnu_pbds;
//void FILEREAD(){freopen("text_input.txt","r",stdin);freopen("output.txt","w",stdout);}
#define ll long long
#define ull unsigned long long
#define pi pair<int,int>
#define pll pair<long long,long long>
#define pli pair<long long,int>
#define pil pair<int,long long>
#define vi vector<int>
#define vll vector<long long>
#define vpi vector<pair<int,int>>
#define vpll vector<pair<long long,long long>>
#define vvi vector<vector<int>>
#define vvll vector<vector<long long>>
#define vvpi vector<vector<pair<int,int>>>
#define vvpll vector<vector<pair<long,long>>>
#define vec vector
#define pr pair
#define fi first
#define se second
#define fr(i,j) for(int i=0;i<j;i++)
#define testcase(x) int x;cin>>x;while(x--)solve()
#define vecinp(v) for(auto &in_vx:v)cin>>in_vx
#define pb push_back
typedef tree<ll,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> ordered_Set;
ordered_Set os;
#define MAX 99999997
#define MOD 92182
#define maxM 1000005
#include<combo.h>
string guess_sentence(int N){
string K = "";
#define sz K.size()
char inital = '#';
// find the inital one
int r = press("AB");if(r)inital = (press("A")==1?'A':'B');else inital = (press("X")==1?'X':'Y');
K += inital;
char C1='B',C2='X',C3='Y';
if(inital == 'B')C1='A';if(inital == 'X')C2='A';if(inital == 'Y')C3='A';
// find the middle ones
for(int i=1;i<N-1;i++){
string qs="";
// K+X+FILL(X) + K+X+FILL(Y) + K+X+FILL(B) + K+Y
qs+=K;qs+=C1;qs+=C1;
qs+=K;qs+=C1;qs+=C2;
qs+=K;qs+=C1;qs+=C3;
qs+=K;qs+=C2;
r = press(qs);
if(r == sz)K+=C3;
else if(r == sz+1)K+=C2;
else K+=C1;
}
// find the last one
string qs = "";
qs+=K;qs+=C1;
qs+=K;qs+=C2;
r = press(qs);
if(r == sz+1){
qs = K;qs+=C1;
r = press(qs);
if(r == sz+1)K+=C1;
else K+=C2;
}
else{
K+=C3;
}
return K;
}
/*
int main(){
int N,K; N = 11; K = 12;
cin>>N>>K;
int H[N-1][2];
int L[N-1];
for(int i=0;i<N-1;i++){
cin >> H[i][0] >> H[i][1] >> L[i];
}
cout << best_path(N,K,H,L);
}*/