Submission #856682

#TimeUsernameProblemLanguageResultExecution timeMemory
856682overwatch9Sails (IOI07_sails)C++17
15 / 100
197 ms9040 KiB
#include <iostream> #include <vector> #include <algorithm> using namespace std; using ll = long long; const int maxn = 1e5; struct stree { #define lc v*2 #define rc v*2+1 vector <pair <int, int>> tree; stree (int sz) { tree = vector <pair <int, int>> (sz*4); } void pushup(int v) { tree[v].first = tree[lc].first; if (tree[lc].first == 0) tree[v].first = tree[rc].first; tree[v].second = tree[rc].second; if (tree[rc].second == 0) tree[v].second = tree[lc].second; } void update(int v, int tl, int tr, int p, int val) { if (tl > p || tr < p) return; if (tl == tr) { tree[v].first += val; tree[v].second += val; return; } int tm = (tl + tr) / 2; update(lc, tl, tm, p, val); update(rc, tm+1, tr, p, val); pushup(v); } int query(int v, int tl, int tr, int p) { if (tl > p || tr < p) return 0; if (tl == tr) return tree[v].first; int tm = (tl + tr) / 2; int a = query(lc, tl, tm, p); if (a == 0) return query(rc, tm+1, tr, p); return 0; } // find index of leftmost value in the range l->r that is non zero int queryl(int v, int tl, int tr, int l, int r) { if (tl > r || tr < l) return 0; if (tree[v].first == 0) return 0; if (tl == tr) return tl; int tm = (tl + tr) / 2; int a = queryl(lc, tl, tm, l, r); if (a == 0) return queryl(rc, tm+1, tr, l, r); return a; } // find index of rightmost value in the range l->r that is non zero int queryr(int v, int tl, int tr, int l, int r) { if (tl > r || tr < l) return 0; if (tree[v].second == 0) return 0; if (tl == tr) return tl; int tm = (tl + tr) / 2; int a = queryr(rc, tm+1, tr, l, r); if (a == 0) return queryr(lc, tl, tm, l, r); return a; } }; struct node { int val = 0, pd = 0; bool up = false; }; struct stree2 { #define lc v*2 #define rc v*2+1 vector <node> tree; stree2 (int sz) { tree = vector <node> (sz*4); } void pushup(int v) { tree[v].val = tree[lc].val + tree[rc].val; } void pushdown(int v, int tl, int tm, int tr) { if (!tree[v].up) return; tree[v].up = false; tree[lc].up = tree[rc].up = true; tree[lc].pd += tree[v].pd; tree[rc].pd += tree[v].pd; tree[lc].val += (tm - tl + 1); tree[rc].val += (tr - tm); tree[v].pd = 0; } void update(int v, int tl, int tr, int l, int r) { if (tl > r || tr < l || l > r) return; if (tl >= l && tr <= r) { tree[v].pd++; tree[v].up = true; tree[v].val += (tr - tl + 1); return; } int tm = (tl + tr) / 2; pushdown(v, tl, tm, tr); update(lc, tl, tm, l, r); update(rc, tm+1, tr, l, r); pushup(v); } int query(int v, int tl, int tr, int l, int r) { if (tl > r || tr < l) return 0; if (tl >= l && tr <= r) return tree[v].val; int tm = (tl + tr) / 2; pushdown(v, tl, tm, tr); int a = query(lc, tl, tm,l, r); int b = query(rc, tm+1, tr,l, r); return a + b; } }; int main() { int n; cin >> n; vector <pair <int, int>> updates(n); for (int i = 0; i < n; i++) cin >> updates[i].first >> updates[i].second; sort(updates.begin(), updates.end()); stree tree(maxn + 5); stree2 tree2(maxn + 5); int r = 0; ll ans = 0; for (int i = 0; i < n; i++) { r = max(r, updates[i].first + 1); int k = updates[i].second; ll res = tree2.query(1, 0, maxn + 4, r - k-1, r-2); ans += res; int lb = tree.queryr(1, 0, maxn + 4, 0, r - k - 1); int rb = r-2; int lx = tree.queryl(1, 0, maxn + 4, r - k, rb); int rx = lb + (k - (rb - lx + 1)) - 1; if (lx == 0) rx = lb + k - 1; tree.update(1, 0, maxn + 4, lb, 1); tree.update(1, 0, maxn + 4, rx+1, -1); if (lx > 0) tree.update(1, 0, maxn + 4, lx, 1); tree2.update(1, 0, maxn + 4, lb, rx); if (lx > 0) tree2.update(1, 0, maxn + 4, lx, rb); } cout << ans << '\n'; }
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