제출 #856615

#제출 시각아이디문제언어결과실행 시간메모리
856615nnhzzzLongest beautiful sequence (IZhO17_subsequence)C++14
100 / 100
3218 ms51544 KiB
// cre: Nguyen Ngoc Hung - Train VOI 2024 :> #include <algorithm> #include <bitset> #include <complex> #include <deque> #include <exception> #include <fstream> #include <functional> #include <iomanip> #include <ios> #include <iosfwd> #include <iostream> #include <istream> #include <iterator> #include <limits> #include <list> #include <locale> #include <map> #include <memory> #include <new> #include <numeric> #include <ostream> #include <queue> #include <set> #include <unordered_set> #include <sstream> #include <stack> #include <stdexcept> #include <streambuf> #include <string> #include <typeinfo> #include <utility> #include <valarray> #include <vector> #include <cstring> #include <unordered_map> #include <cmath> #include <array> #include <cassert> #include <random> using namespace std; #define __nnhzzz__ signed main() #define BIT(i,j) ((i>>j)&1LL) #define MASK(i) (1LL<<i) #define ALL(x) (x).begin(),(x).end() #define SZ(x) (int)(x).size() #define fi first #define se second #define ll long long #define vi vector<int> #define vvi vector<vi> #define pii pair<int,int> #define vpii vector<pii> #define REPDIS(i,be,en,j) for(int i = (be); i<=(en); i+=j) #define REPD(i,be,en) for(int i = (be); i>=(en); i--) #define REP(i,be,en) for(int i = (be); i<=(en); i++) //-------------------------------------------------------------// const int oo = 1e9,LOG = 20,MAXN = 1e5+7,N = 1e2+3; const int MOD = 1e9+7,MOD1 = 1e9+207,MOD2 = 1e9+407,MOD3 = 998244353; //-------------------------------------------------------------// template<typename T1, typename T2> bool mini(T1 &a, T2 b){if(a>b){a=b;return true;}return false;} template<typename T1, typename T2> bool maxi(T1 &a, T2 b){if(a<b){a=b;return true;}return false;} template<typename T> T gcd(T a, T b) { while(b) { a %= b; swap(a,b); } return a; } template<typename T> T lcm(T a, T b) { return a/gcd(a,b)*b; } /* ---------------------------------------------------------------- END OF TEMPLATE ---------------------------------------------------------------- Nguyen Ngoc Hung - nnhzzz Training for VOI24 gold medal ---------------------------------------------------------------- */ int a[MAXN],k[MAXN],dp[MASK(10)|1][MASK(10)|1][11],cnt[MASK(20)|1]; int n; void sub2(){ vi dp(n+3),par(n+3),cnt(2100000,0); REP(i,0,SZ(cnt)-1) cnt[i] = __builtin_popcount(i); REP(i,1,n){ dp[i] = 1; par[i] = 0; } REP(i,1,n){ REP(j,1,i-1){ int val = a[i]&a[j]; if(cnt[val]==k[i]){ if(maxi(dp[i],dp[j]+1)){ par[i] = j; } } } } int res = 0,pos = 0; REP(i,1,n){ if(maxi(res,dp[i])) pos = i; } vi ans; while(pos!=0){ ans.push_back(pos); pos = par[pos]; } reverse(ALL(ans)); cout << res << "\n"; for(const auto &i:ans){ cout << i << " "; } } void sub3(){ vi pos(MASK(8)|1,-1),par(n+3,0),dp(n+3,1); REP(i,0,MASK(8)) cnt[i] = __builtin_popcount(i); REP(i,1,n){ REP(j,0,MASK(8)){ int val = a[i]&j; if(cnt[val]!=k[i] || pos[j]==-1) continue; if(maxi(dp[i],dp[pos[j]]+1)) par[i] = pos[j]; } if(dp[pos[a[i]]]<dp[i]) pos[a[i]] = i; } vi ans; int res = 0,p = 0; REP(i,1,n){ if(maxi(res,dp[i])) p = i; } while(p!=0){ ans.push_back(p); p = par[p]; } reverse(ALL(ans)); cout << res << "\n"; for(const auto &i:ans){ cout << i << " "; } } void sub4(){ // vector<vvi> dp(MASK(10)|1,vvi(MASK(10)|1,vi(11,-1))); REP(i,1,MASK(20)) cnt[i] = __builtin_popcount(i); memset(dp,-1,sizeof dp); vpii f(n+3); pii res = {1,-1}; REP(i,1,n){ int v1 = a[i]&(MASK(10)-1); int v2 = a[i]>>10; f[i] = {1,-1}; REP(pre_v1,0,MASK(10)-1){ int diff_v1 = __builtin_popcount(v1&pre_v1); int diff_v2 = k[i]-diff_v1; if(diff_v2<0 || diff_v2>10) continue; int cur = dp[pre_v1][v2][diff_v2]; if(cur==-1) continue; maxi(f[i],make_pair(f[cur].fi+1,cur)); } maxi(res,make_pair(f[i].fi,i)); REP(nxt_v2,0,MASK(10)-1){ int diff_v2 = cnt[v2&nxt_v2]; int &val = dp[v1][nxt_v2][diff_v2]; if(val!=-1 && f[i].fi<f[val].fi) continue; val = i; } } cout << res.fi << "\n"; vi ans(1,res.se); while(f[ans.back()].se!=-1) ans.push_back(f[ans.back()].se); reverse(ALL(ans)); for(const auto &i:ans){ cout << i << " "; } } void solve(){ cin >> n; REP(i,1,n) cin >> a[i]; REP(i,1,n) cin >> k[i]; if(n<=5000){ sub2(); return ; } int ma = 0; REP(i,1,n) maxi(ma,a[i]); if(ma<=MASK(8)){ sub3(); return ; } sub4(); } __nnhzzz__{ ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); #define name "test" if(fopen(name".inp","r")){ freopen(name".inp","r",stdin); freopen(name".out","w",stdout); } #define name1 "subsequence" if(fopen(name1".in","r")){ freopen(name1".in","r",stdin); freopen(name1".out","w",stdout); } int test = 1; while(test--){ solve(); } cerr << "\nTime elapsed: " << 1000*clock()/CLOCKS_PER_SEC << "ms\n"; return 0; }

컴파일 시 표준 에러 (stderr) 메시지

subsequence.cpp: In function 'int main()':
subsequence.cpp:196:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  196 |         freopen(name".inp","r",stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~
subsequence.cpp:197:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  197 |         freopen(name".out","w",stdout);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~
subsequence.cpp:201:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  201 |         freopen(name1".in","r",stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~
subsequence.cpp:202:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  202 |         freopen(name1".out","w",stdout);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~
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