이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#define fast ios::sync_with_stdio(0);cin.tie(0);
#define s second
#define f first
typedef long long ll;
const ll MOD = 1e9 + 7;
const ll LOGN = 18;
const ll INF = 1e15;
const ll MAXN = 400;
ll expo(ll a, ll b) {
ll res = 1;
while (b) {
if (b & 1)
res = (res * a) % MOD;
a = (a * a) % MOD;
b /= 2;
}
return res;
}
ll dp[MAXN][MAXN][2];
ll fact[5 * MAXN], inv[5 * MAXN];
ll nCr(ll n, ll r) {
return ((fact[n] * inv[r]) % MOD * inv[n-r]) % MOD;
}
int main() {
fast
fact[0] = inv[0] = 1;
for (ll i = 1; i < 5*MAXN; i++) {
fact[i] = (fact[i-1] * i) % MOD;
inv[i] = expo(fact[i], MOD - 2);
}
int N;
cin >> N;
dp[0][0][0] = 1;
for (int i = 1; i <= N; i++) {
for (int last = 0; last <= N; last++) {
for (int now = last; now <= N; now++) {
int rem = N - last;
ll choose = nCr(rem, now - last);
if (now - last != i)
dp[i][now][0] = (dp[i][now][0] + (dp[i-1][last][0] * choose) % MOD) % MOD;
if (i == now - last)
dp[i][now][1] = (dp[i][now][1] + ((dp[i-1][last][0] + dp[i-1][last][1]) * choose) % MOD) % MOD;
else
dp[i][now][1] = (dp[i][now][1] + (dp[i-1][last][1] * choose) % MOD) % MOD;
}
}
}
cout << dp[N][N][1] << "\n";
}
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