이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#define fi first
#define se second
using ll = long long;
const int N = 1e5+5;
//--------------------------------------
int n, k, a[100001];
vector<int> adj[100001];
ll down[100001][101], up[100001][101], ans = 0;
 
void dfs(int u, int par) {
    ll sum = 0;
    for (int v : adj[u]) sum += a[v];
    up[u][1] = sum;
    for (int v : adj[u]) if (v != par) {
        dfs(v, u);
        for (int i = 1; i <= k; i++) ans = max(ans, up[u][i] + down[v][k - i]);
        for (int i = 1; i <= k; i++) {
            down[u][i] = max({down[u][i], down[v][i], down[v][i-1] + sum - a[par]});
            up[u][i] = max({up[u][i], up[v][i], up[v][i-1] + sum - a[v]});
        }
    }
    memset(up[u], 0, sizeof(up[u]));
    up[u][1] = sum;
    reverse(adj[u].begin(), adj[u].end());
    for (int v : adj[u]) if (v != par) {
        for (int i = 1; i <= k; i++) ans = max(ans, up[u][i] + down[v][k-i]);
        for (int i = 1; i <= k; i++)
            up[u][i] = max({up[u][i], up[v][i], up[v][i-1] + sum - a[v]});
    }
}
 
int main() {
    ios::sync_with_stdio(0);
    cin.tie(0), cout.tie(0);
    cin >> n >> k;
    for (int i = 1; i <= n; i++) cin >> a[i];
    for (int i = 1; i < n; i++) {
        int u, v; cin >> u >> v;
        adj[u].push_back(v);
        adj[v].push_back(u);
    }
    dfs(1, 0);
    cout << ans;
}
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