# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
853050 | aykhn | 곤돌라 (IOI14_gondola) | C++14 | 38 ms | 7116 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "gondola.h"
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define pb push_back
#define ins insert
#define infll 0x3F3F3F3F3F3F3F3F
#define inf 0x3F3F3F3F
#define pii pair<int, int>
#define pll pair<ll, ll>
#define mpr make_pair
#define all(v) v.begin(), v.end()
#define fi first
#define se second
const int mod = 1e9 + 9;
int mult(ll a, ll b)
{
return (a * b) % mod;
}
int binpow(ll a, ll b)
{
a %= mod;
ll res = 1;
while (b)
{
if (b & 1) res = mult(res, a);
b >>= 1;
a = mult(a, a);
}
return res;
}
vector<int> ASDASD;
int ok(vector<int> &v)
{
int n = v.size();
set<int> s;
for (int x : v) s.ins(x);
if (s.size() != v.size()) return 0;
vector<int> a(n, 0);
int anc = -1;
for (int i = 0; i < v.size(); i++)
{
if (v[i] <= n)
{
anc = i;
break;
}
}
if (anc == -1)
{
ASDASD = v;
return 1;
}
int shift = n + v[anc] - anc - 1;
for (int i = 0; i < n; i++) a[(i + shift + 10*n) % n] = v[i];
ASDASD = a;
for (int i = 0; i < n; i++)
{
if (a[i] <= n && a[i] != i + 1) return 0;
}
return 1;
}
int valid(int n, int in[])
{
vector<int> v;
for (int i = 0; i < n; i++) v.pb(in[i]);
return ok(v);
}
int replacement(int n, int in[], int ret[])
{
vector<int> v;
for (int i = 0; i < n; i++) v.pb(in[i]);
ok(v);
v = ASDASD;
vector<pii> a;
for (int i = 0; i < v.size(); i++)
{
if (v[i] == i + 1) continue;
a.pb(mpr(v[i], i + 1));
}
sort(all(a));
int j = 0;
int rn = n + 1;
for (int i = 0; i < a.size(); i++)
{
ret[j++] = a[i].se;
while (a[i].fi > rn) ret[j++] = rn++;
rn++;
}
return j;
}
int countReplacement(int n, int in[])
{
vector<int> v;
for (int i = 0; i < n; i++) v.pb(in[i]);
if (!ok(v)) return 0;
v = ASDASD;
vector<pii> a;
for (int i = 0; i < v.size(); i++)
{
if (v[i] == i + 1) continue;
a.pb(mpr(v[i], i + 1));
}
int x = 1;
if (a.size() == v.size()) x = n;
sort(all(a));
int last = n;
int res = 1;
int sz = a.size();
for (int i = 0; i < a.size(); i++)
{
res = mult(res, binpow(sz - i, a[i].fi - last - 1));
last = a[i].fi;
}
return mult(res, x);
}
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