제출 #852376

#제출 시각아이디문제언어결과실행 시간메모리
852376vjudge1휴가 (IOI14_holiday)C++17
100 / 100
265 ms15000 KiB
#include <iostream> #include <vector> #include <algorithm> #include "holiday.h" using namespace std; pair<int, int> a[400005]; long long f[400005], g[400005], res = 0; int d; struct DAY { long long int res, c; }; DAY t[1600005]; void update(int v, int x) { v += 400005; if (x < 0) t[v].c = 0; else t[v].c = 1; t[v].res += x; v /= 2; while (v > 0) { t[v].c = t[v * 2].c + t[v * 2 + 1].c; t[v].res = t[v * 2].res + t[v * 2 + 1].res; v /= 2; } } long long int sum(int v, int l, int r, int x) { if (t[v].c == 0 || x <= 0) return 0; if (t[v].c <= x) return t[v].res; int mid = (l + r) / 2; if (t[v * 2 + 1].c >= x) return sum(v * 2 + 1, mid + 1, r, x); return t[v * 2 + 1].res + sum(v * 2, l, mid, x - t[v * 2 + 1].c); } int ll = 0, rr = -1; void trya(int x, int y) { while (ll > x) { ll--; update(a[ll].second, a[ll].first); } while (rr < y) { rr++; update(a[rr].second, a[rr].first); } while (ll < x) { update(a[ll].second, -a[ll].first); ll++; } while (rr > y) { update(a[rr].second, -a[rr].first); rr--; } } void dnc(int l, int r, int x, int y, int k) { if (l > r) return; int mid = (l + r) / 2; trya(x, mid); int h = x; for (int i = x; i <= min(mid, y) && i <= k; i++) { int c = (k - i) + (mid - i); if (d - c > 0) { long long int k = sum(1, 0, 400004, d - c); if (f[mid] <= k) { f[mid] = k; res = max(res, k); h = i; } } update(a[i].second, -a[i].first); ll++; } dnc(l, mid - 1, x, h, k); dnc(mid + 1, r, h, y, k); } void dnc2(int l, int r, int x, int y, int k) { if (l > r) return; int mid = (l + r) / 2; trya(mid, y); int h = y; for (int i = y; i >= max(mid, x) && i >= k; i--) { int c = (i - k) + (i - mid); if (d - c > 0) { long long int k = sum(1, 0, 400004, d - c); if (g[mid] <= k) { g[mid] = k; res = max(res, k); h = i; } } update(a[i].second, -a[i].first); rr--; } dnc2(l, mid - 1, x, h, k); dnc2(mid + 1, r, h, y, k); } long long int findMaxAttraction(int n, int k, int dd, int attraction[]) { vector<pair<int, int>> v; for (int i = 0; i < n; i++) { v.push_back({attraction[i], i}); } sort(v.begin(), v.end()); for (int i = 0; i < n; i++) { a[v[i].second] = {v[i].first, i}; } d = dd; dnc(k, n - 1, 0, n - 1, k); dnc2(0, k, 0, n - 1, k); return res; }
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