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답안 #85191

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
85191 2018-11-18T21:07:21 Z radoslav11 Regions (IOI09_regions) C++14
100 / 100
 7264 ms 127932 KB 
/*
	We will split regions in two types - heavy and light. Formally if CountVertices(R) >= B then R is heavy and if CountVertices(R) < B it's light.

	We have 3 cases:
	1) R1 and R2 are light. We can easly solve such queries in O((CountVertices(R1) + CountVertices(R2)) * log N) < O(B * log N) 
	2) R1 is heavy 
	3) R2 is heavy

	Let's precompute the answers for all queries of type 2 and 3. The main observation is that there are O(N * N / B) such queries and we can solve them all in O(N * N / B * log N) time. 
*/

#include <bits/stdc++.h>
#define endl '\n'

//#pragma GCC optimize ("O3")
//#pragma GCC target ("sse4")

#define SZ(x) ((int)x.size())
#define ALL(V) V.begin(), V.end()
#define L_B lower_bound
#define U_B upper_bound

using namespace std;
template<class T, class T2> inline int chkmax(T &x, const T2 &y) { return x < y ? x = y, 1 : 0; }
template<class T, class T2> inline int chkmin(T &x, const T2 &y) { return x > y ? x = y, 1 : 0; }
const int MAXN = (int)200042;
const int MAXR = 25042;
const int B = 500;

struct fenwick
{
	int tr[MAXN];
	int n;

	void init(int sz)
	{
		n = sz;
		for(int i = 0; i <= n; i++)
			tr[i] = 0;
	}

	void add(int idx, int x)
	{
		for(; idx <= n; idx += (idx & -idx))
			tr[idx] += x;
	}

	int query(int idx)
	{
		int ret = 0;
		for(; idx > 0; idx -= (idx & -idx))
			ret += tr[idx];
		return ret;
	}

	int query(int l, int r) { return query(r) - query(l - 1); }
};

struct fenwick_range
{
	int tr[MAXN];
	int n;

	void init(int sz)
	{
		n = sz + 1;
		for(int i = 0; i <= n; i++)
			tr[i] = 0;
	}

	void add(int idx, int x)
	{
		for(; idx <= n; idx += (idx & -idx))
			tr[idx] += x;
	}

	int query(int idx)
	{
		int ret = 0;
		for(; idx > 0; idx -= (idx & -idx))
			ret += tr[idx];
		return ret;
	}

	void update(int l, int r, int x)
	{
		add(l, x);
		add(r + 1, -x);
	}
};

fenwick T1;
fenwick_range T2;

int n, k, q;
vector<int> r[MAXN], adj[MAXN];

void read()
{
	cin >> n >> k >> q;

	int dummy;
	cin >> dummy;

	r[dummy].push_back(1);

	for(int i = 2; i <= n; i++)
	{
		int par;
		cin >> par >> dummy;
		adj[par].push_back(i);
		r[dummy].push_back(i);
	}
}

int st[MAXN], en[MAXN], dfs_time;

void dfs(int u, int pr)
{
	st[u] = ++dfs_time;
	for(int v: adj[u])
		if(v != pr)
			dfs(v, u);
	en[u] = dfs_time;
}

int h_id[MAXR], rv[B];
int64_t answer_t2[B][MAXR];
int64_t answer_t3[MAXR][B];

void solve()
{
	dfs(1, 1);
	T1.init(n);
	T2.init(n);

	int id = 0;
	for(int i = 1; i <= k; i++)
		if(SZ(r[i]) >= B) 
			h_id[i] = ++id, rv[id] = i;

	for(int i = 1; i <= id; i++)
	{
		int r1 = rv[i];
		for(int i: r[r1])
			T2.update(st[i], en[i], 1);

		for(int r2 = 1; r2 <= k; r2++)
			for(int v: r[r2])
				answer_t2[i][r2] += T2.query(st[v]);

		for(int i: r[r1])
			T2.update(st[i], en[i], -1);
	}
	
	for(int i = 1; i <= id; i++)
	{
		int r2 = rv[i];
		for(int i: r[r2])
			T1.add(st[i], 1);

		for(int r1 = 1; r1 <= k; r1++)
			for(int v: r[r1])
				answer_t3[r1][i] += T1.query(st[v], en[v]);

		for(int i: r[r2])
			T1.add(st[i], -1);
	}

	while(q--)
	{
		int r1, r2;
		cin >> r1 >> r2;

		if(h_id[r1]) cout << answer_t2[h_id[r1]][r2];
		else if(h_id[r2]) cout << answer_t3[r1][h_id[r2]];
		else
		{
			for(int i: r[r2]) T1.add(st[i], 1);
			int64_t answer = 0;
			for(int j: r[r1]) answer += T1.query(st[j], en[j]);
			for(int i: r[r2]) T1.add(st[i], -1);

			cout << answer << endl;
		}
		
		cout << endl << flush;
	}
}

int main()
{
	ios_base::sync_with_stdio(false);
	cin.tie(NULL);

	read();
	solve();
	return 0;
}

Subtask #1
15.0 / 15.0

# 결과 실행 시간 메모리 Grader output
1 Correct 9 ms 9720 KB Output is correct
2 Correct 10 ms 9800 KB Output is correct
3 Correct 10 ms 9800 KB Output is correct
4 Correct 14 ms 9896 KB Output is correct
5 Correct 16 ms 9940 KB Output is correct
6 Correct 26 ms 9968 KB Output is correct
7 Correct 37 ms 9968 KB Output is correct
8 Correct 43 ms 9968 KB Output is correct
9 Correct 57 ms 10368 KB Output is correct
10 Correct 83 ms 10496 KB Output is correct
11 Correct 139 ms 10680 KB Output is correct
12 Correct 161 ms 11192 KB Output is correct
13 Correct 222 ms 11192 KB Output is correct
14 Correct 318 ms 11448 KB Output is correct
15 Correct 457 ms 13880 KB Output is correct

Subtask #2
85.0 / 85.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1520 ms 15388 KB Output is correct
2 Correct 1729 ms 15388 KB Output is correct
3 Correct 3293 ms 17464 KB Output is correct
4 Correct 362 ms 17464 KB Output is correct
5 Correct 339 ms 17464 KB Output is correct
6 Correct 1234 ms 37848 KB Output is correct
7 Correct 2703 ms 37848 KB Output is correct
8 Correct 2610 ms 57920 KB Output is correct
9 Correct 4371 ms 57920 KB Output is correct
10 Correct 7264 ms 57920 KB Output is correct
11 Correct 6899 ms 57920 KB Output is correct
12 Correct 1752 ms 75708 KB Output is correct
13 Correct 2555 ms 75944 KB Output is correct
14 Correct 2950 ms 91168 KB Output is correct
15 Correct 4644 ms 122468 KB Output is correct
16 Correct 4981 ms 127932 KB Output is correct
17 Correct 4709 ms 127932 KB Output is correct