oj.uz

답안 #85190

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
85190 2018-11-18T21:04:13 Z radoslav11 Regions (IOI09_regions) C++14
55 / 100
 7683 ms 130508 KB 
/*
	We will split regions in two types - heavy and light. Formally if CountVertices(R) >= B then R is heavy and if CountVertices(R) < B it's light.

	We have 3 cases:
	1) R1 and R2 are light. We can easly solve such queries in O((CountVertices(R1) + CountVertices(R2)) * log N) < O(B * log N) 
	2) R1 is heavy 
	3) R2 is heavy

	Let's precompute the answers for all queries of type 2 and 3. The main observation is that there are O(N * N / B) such queries and we can solve them all in O(N * N / B * log N) time. 
*/

#include <bits/stdc++.h>
#define endl '\n'

//#pragma GCC optimize ("O3")
//#pragma GCC target ("sse4")

#define SZ(x) ((int)x.size())
#define ALL(V) V.begin(), V.end()
#define L_B lower_bound
#define U_B upper_bound

using namespace std;
template<class T, class T2> inline int chkmax(T &x, const T2 &y) { return x < y ? x = y, 1 : 0; }
template<class T, class T2> inline int chkmin(T &x, const T2 &y) { return x > y ? x = y, 1 : 0; }
const int MAXN = (int)200042;
const int MAXR = 25042;
const int B = (int)700;

struct fenwick
{
	int tr[MAXN];
	int n;

	void init(int sz)
	{
		n = sz;
		for(int i = 0; i <= n; i++)
			tr[i] = 0;
	}

	void add(int idx, int x)
	{
		for(; idx <= n; idx += (idx & -idx))
			tr[idx] += x;
	}

	int query(int idx)
	{
		int ret = 0;
		for(; idx > 0; idx -= (idx & -idx))
			ret += tr[idx];
		return ret;
	}

	int query(int l, int r) { return query(r) - query(l - 1); }
};

struct fenwick_range
{
	int tr[MAXN];
	int n;

	void init(int sz)
	{
		n = sz + 1;
		for(int i = 0; i <= n; i++)
			tr[i] = 0;
	}

	void add(int idx, int x)
	{
		for(; idx <= n; idx += (idx & -idx))
			tr[idx] += x;
	}

	int query(int idx)
	{
		int ret = 0;
		for(; idx > 0; idx -= (idx & -idx))
			ret += tr[idx];
		return ret;
	}

	void update(int l, int r, int x)
	{
		add(l, x);
		add(r + 1, -x);
	}
};

fenwick T1;
fenwick_range T2;

int n, k, q;
vector<int> r[MAXN], adj[MAXN];

void read()
{
	cin >> n >> k >> q;

	int dummy;
	cin >> dummy;

	r[dummy].push_back(1);

	for(int i = 2; i <= n; i++)
	{
		int par;
		cin >> par >> dummy;
		adj[par].push_back(i);
		r[dummy].push_back(i);
	}
}

int st[MAXN], en[MAXN], dfs_time;

void dfs(int u, int pr)
{
	st[u] = ++dfs_time;
	for(int v: adj[u])
		if(v != pr)
			dfs(v, u);
	en[u] = dfs_time;
}

int h_id[MAXR], rv[B];
int64_t answer_t2[B][MAXR];
int64_t answer_t3[MAXR][B];

void solve()
{
	dfs(1, 1);
	T1.init(n);
	T2.init(n);

	int id = 0;
	for(int i = 1; i <= k; i++)
		if(SZ(r[i]) >= B) 
			h_id[i] = ++id, rv[id] = h_id[i];

	for(int i = 1; i <= id; i++)
	{
		int r1 = rv[i];
		for(int i: r[r1])
			T2.update(st[i], en[i], 1);

		for(int r2 = 1; r2 <= k; r2++)
			for(int v: r[r2])
				answer_t2[i][r2] += T2.query(st[v]);

		for(int i: r[r1])
			T2.update(st[i], en[i], -1);
	}
	
	for(int i = 1; i <= id; i++)
	{
		int r2 = rv[i];
		for(int i: r[r2])
			T1.add(st[i], 1);

		for(int r1 = 1; r1 <= k; r1++)
			for(int v: r[r1])
				answer_t3[r1][i] += T1.query(st[v], en[v]);

		for(int i: r[r2])
			T1.add(st[i], -1);
	}

	while(q--)
	{
		int r1, r2;
		cin >> r1 >> r2;

		if(h_id[r1]) cout << answer_t2[h_id[r1]][r2];
		else if(h_id[r2]) cout << answer_t3[r1][h_id[r2]];
		else
		{
			for(int i: r[r2]) T1.add(st[i], 1);
			int64_t answer = 0;
			for(int j: r[r1]) answer += T1.query(st[j], en[j]);
			for(int i: r[r2]) T1.add(st[i], -1);

			cout << answer << endl;
		}
		
		cout << endl << flush;
	}
}

int main()
{
	ios_base::sync_with_stdio(false);
	cin.tie(NULL);

	read();
	solve();
	return 0;
}

Subtask #1
15.0 / 15.0

# 결과 실행 시간 메모리 Grader output
1 Correct 10 ms 9640 KB Output is correct
2 Correct 11 ms 9800 KB Output is correct
3 Correct 12 ms 9992 KB Output is correct
4 Correct 14 ms 9992 KB Output is correct
5 Correct 14 ms 9992 KB Output is correct
6 Correct 27 ms 10012 KB Output is correct
7 Correct 39 ms 10012 KB Output is correct
8 Correct 41 ms 10012 KB Output is correct
9 Correct 48 ms 10396 KB Output is correct
10 Correct 93 ms 10396 KB Output is correct
11 Correct 152 ms 10780 KB Output is correct
12 Correct 156 ms 11184 KB Output is correct
13 Correct 218 ms 11184 KB Output is correct
14 Correct 343 ms 11440 KB Output is correct
15 Correct 374 ms 14012 KB Output is correct

Subtask #2
40.0 / 85.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 1796 ms 15292 KB Output isn't correct
2 Incorrect 1861 ms 15292 KB Output isn't correct
3 Incorrect 3643 ms 17340 KB Output isn't correct
4 Correct 378 ms 17340 KB Output is correct
5 Correct 431 ms 17340 KB Output is correct
6 Correct 1961 ms 17340 KB Output is correct
7 Correct 2820 ms 17340 KB Output is correct
8 Correct 2814 ms 18620 KB Output is correct
9 Correct 4438 ms 18748 KB Output is correct
10 Correct 7683 ms 23484 KB Output is correct
11 Correct 7562 ms 23484 KB Output is correct
12 Incorrect 1985 ms 76976 KB Output isn't correct
13 Incorrect 2929 ms 77116 KB Output isn't correct
14 Incorrect 3636 ms 93280 KB Output isn't correct
15 Incorrect 5198 ms 124748 KB Output isn't correct
16 Incorrect 4962 ms 130508 KB Output isn't correct
17 Incorrect 5005 ms 130508 KB Output isn't correct