이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "closing.h"
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef __int128 lll;
typedef long double ld;
typedef pair<ll, ll> pll;
typedef pair<ld, ld> pld;
#define MAX 9223372036854775807LL
#define MIN -9223372036854775807LL
#define INF 0x3f3f3f3f3f3f3f3f
#define fi first
#define se second
#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); cout << fixed; cout.precision(10);
#define sp << " "
#define en << "\n"
#define compress(v) sort(v.begin(), v.end()), v.erase(unique(v.begin(), v.end()), v.end())
ll n, x, y;
vector<pll> vec[500010];
ll dist1[500010], dist2[500010];
ll yuk[500010], chk[500010];
ll A[500010], B[500010], C[500010];
ll D[500010];
void dfs1(ll here, ll pa)
{
for(auto &i : vec[here])
{
if(i.fi == pa)
continue;
dist1[i.fi] = dist1[here] + i.se;
dfs1(i.fi, here);
}
}
void dfs2(ll here, ll pa)
{
for(auto &i : vec[here])
{
if(i.fi == pa)
continue;
yuk[i.fi] = here;
dist2[i.fi] = dist2[here] + i.se;
dfs2(i.fi, here);
}
}
int max_score(int N, int X, int Y, long long K, vector<int> U, vector<int> V, vector<int> W)
{
n = N;
x = X + 1;
y = Y + 1;
ll ans = -INF;
for(ll i = 1 ; i <= n * 2 + 3 ; i++)
{
vec[i].clear();
dist1[i] = dist2[i] = yuk[i] = chk[i] = 0;
}
for(ll i = 0 ; i <= n * 2 + 3 ; i++)
A[i] = B[i] = C[i] = D[i] = INF;
A[0] = B[0] = C[0] = D[0] = 0;
for(ll i = 0 ; i < n - 1 ; i++)
{
vec[U[i] + 1].push_back({V[i] + 1, W[i]});
vec[V[i] + 1].push_back({U[i] + 1, W[i]});
}
dfs1(x, 0);
dfs2(y, 0);
vector<ll> vvv;
for(ll i = 1 ; i <= n ; i++)
{
vvv.push_back(dist1[i]);
vvv.push_back(dist2[i]);
}
sort(vvv.begin(), vvv.end());
ll hap = 0;
for(ll i = 0 ; i < (ll)vvv.size() ; i++)
{
hap += vvv[i];
if(hap <= K)
ans = max(ans, i + 1);
}
vector<ll> vv;
for(ll i = x ; i != y ; i = yuk[i])
{
vv.push_back(i);
chk[i] = 1;
}
vv.push_back(y);
chk[y] = 1;
vector<ll> vv2, vv3;
ll len = (ll)vv.size();
A[len * 2] = 0;
for(auto &i : vv)
{
vv2.push_back(dist1[i]);
vv2.push_back(dist2[i]);
vv3.push_back(max(dist1[i], dist2[i]) - dist1[i]);
vv3.push_back(max(dist1[i], dist2[i]) - dist2[i]);
A[len * 2] += max(dist1[i], dist2[i]);
}
sort(vv2.begin(), vv2.end());
sort(vv3.begin(), vv3.end());
reverse(vv3.begin(), vv3.end());
ll cc = 0;
for(ll i = 1 ; i <= len ; i++)
A[i] = A[i - 1] + vv2[i - 1];
for(ll i = len * 2 - 1 ; i > len ; i--)
A[i] = A[i + 1] - vv3[cc++];
for(ll i = 0 ; i <= len ; i++)
A[i] = A[i + len];
for(ll i = len + 1 ; i <= len * 2 ; i++)
A[i] = INF;
vector<pll> vv4;
for(ll i = 1 ; i <= n ; i++)
{
if(!chk[i])
vv4.push_back({min(dist1[i], dist2[i]), max(dist1[i], dist2[i])});
}
vector<ll> vv5;
vector<pll> vv6;
ll minn = INF;
for(auto &i : vv4)
{
if(i.fi * 2 <= i.se)
{
vv5.push_back(i.fi);
vv5.push_back(i.se - i.fi);
}
else
{
vv6.push_back(i);
minn = min(minn, i.fi);
}
}
ll nam = (ll)vv6.size();
sort(vv5.begin(), vv5.end());
for(ll i = 0 ; i < (ll)vv5.size() ; i++)
B[i + 1] = B[i] + vv5[i];
if(nam >= 1)
C[1] = minn;
multiset<pll> st1;
multiset<ll> st3, st2;
for(auto &i : vv6)
{
st1.insert({i.se, i.fi - i.se});
st3.insert(i.fi);
}
ll sum = 0;
for(ll i = 2 ; i <= nam * 2 ; i++)
{
if(i % 2 == 0)
{
sum += (*st1.begin()).fi;
st3.erase(st3.find((*st1.begin()).fi + (*st1.begin()).se));
st2.insert((*st1.begin()).se);
st1.erase(st1.find(*st1.begin()));
C[i] = sum;
}
else
{
C[i] = INF;
C[i] = min(C[i], sum + (*st3.begin()));
if(!st1.empty())
C[i] = min(C[i], sum + (*st2.begin()) + (*st1.begin()).fi);
}
}
ll p1 = 1, p2 = 1;
cc = 1;
D[0] = A[0];
while(1)
{
if(A[p1] == INF && B[p2] == INF)
break;
if(A[p1] == INF)
{
D[cc] = D[cc - 1] + B[p2] - B[p2 - 1];
p2++, cc++;
}
else if(B[p2] == INF)
{
D[cc] = D[cc - 1] + A[p1] - A[p1 - 1];
p1++, cc++;
}
else
{
if(B[p2] - B[p2 - 1] < A[p1] - A[p1 - 1])
{
D[cc] = D[cc - 1] + B[p2] - B[p2 - 1];
p2++, cc++;
}
else
{
D[cc] = D[cc - 1] + A[p1] - A[p1 - 1];
p1++, cc++;
}
}
}
ll p = -1;
for(ll i = 0 ; i <= n * 2 ; i++)
{
if(C[i] != INF)
p = i;
}
for(ll i = 0 ; i <= n * 2 ; i++)
{
if(D[i] == INF)
break;
while(p >= 0 && D[i] + C[p] > K)
p--;
if(p < 0)
break;
ans = max(ans, i + p + len);
}
/*for(ll i = 0 ; i <= n * 2 ; i++)
cout << A[i] sp;
cout en;
for(ll i = 0 ; i <= n * 2 ; i++)
cout << B[i] sp;
cout en;
for(ll i = 0 ; i <= n * 2 ; i++)
cout << D[i] sp;
cout en;
for(ll i = 0 ; i <= n * 2 ; i++)
cout << C[i] sp;
cout en;*/
return ans;
}
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