제출 #851724

#제출 시각아이디문제언어결과실행 시간메모리
851724Muaath_5추월 (IOI23_overtaking)C++17
9 / 100
4 ms604 KiB
#include <bits/stdc++.h>
//#define int long long
#define ll long long
#define endl '\n'
#define pii pair<int,int>
#define vint vector<int>
#define vll vector<ll>
#define vpii vector<pii>
#define pb push_back
#define se second
#define fi first
#define all(x) x.begin(), x.end()
#define graph vector<vll>
using namespace std;
const int N = (int)2e5 + 69;
const int mod = (int)1e4 + 7;
const int naser = 3999, tourist = 3816;
int power(int a, int b) { int ans = 1; while (b) { if (b % 2) ans *= a; a *= a; b /= 2; } return ans; }
 
ll n, x, m, l, y, stn;
vll w, s, t;
graph arv, srt,arvsrt;
 
bool cmp(int a, int b) {
    if (arv[stn][a] == arv[stn][b])
        return w[a] < w[b];
    return arv[stn][a] < arv[stn][b];
}
bool cmp2(int a, int b) {
    return arv[stn][a] < b;
}
void init(int L, int N, vll T, vint W, int X, int M, vint S) {
    n = N;
    t = T;
    w.resize(n);
    for (int i = 0; i < n; i++)
        w[i] = W[i];
    x = X;
    m = M;
    s.resize(m);
    for (int i = 0; i < m; i++)
        s[i] = S[i];
    arv.resize(m, vll(n));
    srt.resize(m, vll(n));
    arvsrt.resize(m);
    vector<ll> tmp;
    for (int i = 0; i < n; i++) {
        arv[0][i] = t[i];
        arvsrt[0].pb(t[i]);
        tmp.pb(i);
    }
    sort(all(arvsrt[0]));
 
    for (int i = 1; i < m; i++) {
        stn = i-1;
        sort(all(tmp), cmp);
        for (int j = 0; j < n; j++)
            srt[i][j] = tmp[j];
        for (int j = 0; j < n; j++) {
            int bus = srt[i][j];
            int prv = (j ? srt[i][j - 1] : srt[i][j]);
            arv[i][bus] = arv[i - 1][bus] + (s[i] - s[i - 1]) * w[bus];
            if (arv[i - 1][prv] < arv[i - 1][bus])
                arv[i][bus] = max(arv[i][bus], arv[i][prv]);
            arvsrt[i].pb(arv[i][bus]);
        }
		sort(all(srt[i]));
        sort(all(arvsrt[i]));
    }
}
 
long long arrival_time(long long y) {
    ll ans = y;
    for (int i = 0; i < m - 1; i++) {
        ll ex = ans + (s[i+1] - s[i]) * x;
        if (ans <= arvsrt[i][0])
            ans = ex;
        else {
            int idx = 0;
            while (ans > arvsrt[i][idx] && idx < n)
                idx++;
            int prv = srt[i+1][idx - 1];
            if (ex < arv[i+1][prv])
                ans = arv[i+1][prv];
            else
                ans = ex;
        }
    }
    return ans;
}
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