# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
850759 | Litusiano | A Difficult(y) Choice (BOI21_books) | C++17 | 1 ms | 1524 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
/*
SAMPLE GRADER for task BOOKS
USAGE:
place together with your solution and books.h in the same directory, then:
g++ <flags> sample_grader.cpp <solution_file>
e.g.:
g++ -std=c++17 sample_grader.cpp books.cpp
INPUT/OUTPUT:
The sample grader expects on standard input two lines. The first line should
contain the four integers N, K, A and S. The second line should contain a list
of N integers, the sequence of difficulties x_1 x_2 ... x_N which has to be
strictly increasing. Then, the grader writes to standard output a protocol of
all grader functions called by your program.
At the end, the grader prints your verdict.
*/
#include<bits/stdc++.h>
#include"books.h"
using namespace std;
typedef long long ll;
void solve(int N, int K, long long A, int S) {
// TODO implement this function
vector<long long> x(N+1,-1);
long long sm = 0;
for(int i = 1; i<=K; i++){
x[i] = skim(i);
sm += x[i];
}
if(sm > 2*A || K == N) impossible();
if(sm >= A){
vector<int> ans(K); iota(ans.begin(),ans.end(),1);
answer(ans);
return;
}
// get the swap
int l = K-1; int r = N+1;
while(r > l+1){
int m = (l+r)/2;
if(x[m] == -1) x[m] = skim(m);
long long s1 = sm;
if(x[m] >= A) r = m;
else l = m;
}
long long s1 = sm;
s1-=x[K]; s1+=x[r];
if(A<= s1 && s1 <= 2*A){
vector<int> ans;
for(int i = 1; i<K; i++) ans.push_back(i);
ans.push_back(r);
answer(ans);
}
// EL FINAL ES 2*A?
int idx = N-K+1; // N - 1 + K - 1
set<int> ans;
for(int i = 1; i<=K;i++) ans.insert(i);
for(int i = K; i>=1; i--){
// fem els minims canvis
if(x[idx] == -1) x[idx] = skim(idx);
sm -= x[i];
sm+=x[idx];
ans.erase(i); ans.insert(idx);
if(A <= sm && sm <= 2*A){
vector<int> a;
for(auto x : ans) a.push_back(x);
answer(a);
}
idx++;
}
impossible();
}
컴파일 시 표준 에러 (stderr) 메시지
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