Submission #850401

#TimeUsernameProblemLanguageResultExecution timeMemory
850401eltu0815Closing Time (IOI23_closing)C++17
35 / 100
1051 ms32956 KiB
#include "closing.h" #include <bits/stdc++.h> #define MAX 200005 using namespace std; typedef long long ll; typedef pair<int, int> pii; int visited[MAX], parent[MAX]; vector<pii> graph[MAX]; ll tmp[MAX]; ll cost1[MAX], cost2[MAX]; ll dist1[MAX], dist2[MAX]; void init(int node, int par) { parent[node] = par; for(auto [v, w] : graph[node]) if(v != par) init(v, node); } void dfs(int node, int par, ll dist[]) { for(auto [v, w] : graph[node]) if(v != par) { dist[v] = dist[node] + w; dfs(v, node, dist); } } ll c[MAX]; vector<int> path; int max_score(int N, int X, int Y, long long K, vector<int> U, vector<int> V, vector<int> W) { path.clear(); for(int i = 0; i < N; ++i) graph[i].clear(); for(int i = 0; i < N; ++i) dist1[i] = dist2[i] = visited[i] = c[i] = 0; for(int i = 0; i < N - 1; ++i) { graph[U[i]].push_back({V[i], W[i]}); graph[V[i]].push_back({U[i], W[i]}); } init(0, -1); dfs(X, -1, dist1); dfs(Y, -1, dist2); int node = X; while(node != -1) visited[node]++, node = parent[node]; node = Y; int flag = 0; while(node != -1) { if(visited[node] == 1 && !flag) flag = 1; else if(flag) visited[node]--; else visited[node]++; node = parent[node]; } node = X; while(node != -1 && visited[node]) { path.push_back(node); node = parent[node]; } path.pop_back(); node = Y; vector<int> path2; while(node != -1 && visited[node]) { path2.push_back(node); node = parent[node]; } reverse(path2.begin(), path2.end()); for(auto v : path2) path.push_back(v); int p = 0, q = path.size() - 1; for(int i = 1; i <= 2 * N; ++i) cost1[i] = (ll)(2e18); for(int i = 1; i <= 2 * N; ++i) { int u = p == (int)path.size() ? -1 : path[p]; int v = q == -1 ? -1 : path[q]; if(u == -1 && v == -1) break; if(u == -1) { cost1[i] = cost1[i - 1] + dist2[v] - c[v]; c[v] = dist2[v]; --q; } else if(v == -1) { cost1[i] = cost1[i - 1] + dist1[u] - c[u]; c[u] = dist1[u]; ++p; } else if(dist1[u] - c[u] <= dist2[v] - c[v]) { cost1[i] = cost1[i - 1] + dist1[u] - c[u]; c[u] = dist1[u]; ++p; } else { cost1[i] = cost1[i - 1] + dist2[v] - c[v]; c[v] = dist2[v]; --q; } } for(int i = 1; i <= 2 * N; ++i) cost2[i] = (ll)(2e18); for(int i = 0; i < N; ++i) { if(visited[i]) continue; for(int j = 0; j <= 2 * N; ++j) tmp[j] = cost2[j]; for(int j = 1; j <= 2 * N; ++j) { tmp[j] = min(tmp[j], cost2[j - 1] + min(dist1[i], dist2[i])); if(j >= 2) tmp[j] = min(tmp[j], cost2[j - 2] + max(dist1[i], dist2[i])); } for(int j = 0; j <= 2 * N; ++j) cost2[j] = tmp[j]; } int mx = 0; for(int i = 2 * N, p = 0; i >= 0; --i) { while(p < 2 * N && cost1[i] + cost2[p + 1] <= K) ++p; if(cost1[i] + cost2[p] <= K) mx = max(mx, i + p); } return mx; }
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