#include<cstdio>
#include<string.h>
#include"grader.h"
#include"lang.h"
#define MOD 65536
int lang_freq[60][70000];
long long lang_flow1[60][70000];
long long lang_flow2[60][70000];
long long lang_flow3[60][70000];
int did[60];
long long f1(int a,int b)
{
return ((a<<4)^b)%MOD;
}
long long f2(int a,int b,int c)
{
return ((a<<8)^(b<<4)^c)%MOD;
}
long long f3(int a,int b,int c,int d)
{
return ((a<<12)^(b<<8)^(c<<4)^d)%MOD;
}
void excerpt(int *E)
{
int ans=0;
long long ansp=0;
long long pos[60]={0};
for(int i=0;i<56;i++)
{
for(int j=0;j<100;j++)
{
pos[i]+=lang_freq[i][E[j]];
if(j>0)pos[i]+=lang_flow1[i][f1(E[j-1],E[j])]*300000;
if(j>1)pos[i]+=lang_flow2[i][f2(E[j-2],E[j-1],E[j])]*100000001;
if(j>2)pos[i]+=lang_flow3[i][f3(E[j-3],E[j-2],E[j-1],E[j])]*100000000000;
}
pos[i]/=did[i]+1;
if(ansp<pos[i])ansp=pos[i],ans=i;
}
int lang=language(ans);
for(int i=0;i<100;i++)
{
lang_freq[lang][E[i]]++;
if(i>0)
{
lang_flow1[lang][f1(E[i-1],E[i])]++;
}
if(i>1)
{
lang_flow2[lang][f2(E[i-2],E[i-1],E[i])]++;
}
if(i>2)
{
lang_flow3[lang][f3(E[i-3],E[i-2],E[i-1],E[i])]++;
}
}
}
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
3506 ms |
65716 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Partially correct |
3014 ms |
65636 KB |
Output is partially correct - 80.93% |