Submission #848614

#	Time	Username	Problem	Language	Result	Execution time	Memory
848614		wakandaaa	Luxury burrow (IZhO13_burrow)	C++17	100 / 100	509 ms	8536 KiB

burrow

#include <bits/stdc++.h>

using namespace std;

#define file ""

#define mp make_pair
#define fi first
#define se second
#define all(x) x.begin(), x.end()

#define getbit(x, i) (((x) >> (i)) & 1)
#define bit(x) (1LL << (x))
#define popcount __builtin_popcountll

mt19937_64 rd(chrono::steady_clock::now().time_since_epoch().count());
int rand(int l, int r) {
    return l + rd() % (r - l + 1);
}

const int N = 1e3 + 5;
const int mod = (int)1e9 + 7; // 998244353;
const int lg = 25; // lg + 1
const int oo = 1e9;
const long long ooo = 1e18;

template<class X, class Y> bool mini(X &a, Y b) {
    return a > b ? (a = b, true) : false;
}
template<class X, class Y> bool maxi(X &a, Y b) {
    return a < b ? (a = b, true) : false;
}
void add(int &a, int b) {
    a += b;
    if (a >= mod) a -= mod;
    if (a < 0) a += mod;
}

int m, n, k;
int a[N][N], x[N][N];
int h[N], l[N], r[N];

int calc(int c) {
	memset(a, 0, sizeof a);
	memset(h, 0, sizeof h);
	memset(l, 0, sizeof l);
	memset(r, 0, sizeof r);

	int res = 0;
	for (int i = 1; i <= m; ++i)
		for (int j = 1; j <= n; ++j) a[i][j] = (x[i][j] >= c);

    for (int i = 1; i <= m; ++i) {
    	for (int j = 1; j <= n; ++j) 
    		if (a[i][j] == 1)
    			h[j]++;
    		else
    			h[j] = 0;
 
    	stack<int> st;
    	for (int j = 1; j <= n; ++j) {
    		while (st.size() && h[st.top()] >= h[j]) st.pop();
    		l[j] = st.size() ? st.top() : 0;
    		st.push(j);
    	}
    	st = stack<int>{};
    	for (int j = n; j >= 1; --j) {
    		while (st.size() && h[st.top()] >= h[j]) st.pop();
    		r[j] = st.size() ? st.top() : n + 1;
    		st.push(j);
    	}
 
    	for (int j = 1; j <= n; ++j) {
    		int t = h[j] * (r[j] - l[j] - 1);
    		res = max(res, t);
    	}
    }
	return res;
}

int main() {
    ios::sync_with_stdio(false);
    cin.tie(0);

    // freopen(file".inp", "r", stdin);
    // freopen(file".out", "w", stdout);

    cin >> m >> n >> k;
    for (int i = 1; i <= m; ++i)
    	for (int j = 1; j <= n; ++j) cin >> x[i][j];

    int l = 0, r = 1e9;

	int res = 0;
	while (l <= r) {
		int mid = (l + r) / 2;
		if (calc(mid) >= k) {
			res = mid;
			l = mid + 1;
		} else r = mid - 1;
	}

	cout << res << ' ' << calc(res);

    return 0;
}

/*
3 5 2
5 7 5 5 5
8 5 5 7 5
8 5 8 8 8

8 3
*/

• Subtask 1: 100 / 100