이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
//#define int long long
#define endl '\n'
#define pii pair<int,int>
#define vint vector<int>
#define vll vector<long long>
#define vpii vector<pii>
#define pb push_back
#define se second
#define fi first
#define all(x) x.begin(), x.end()
#define graph vector<vector<int>>
using namespace std;
const int N = (int)2e5 + 69;
const int mod = (int)1e4 + 7;
const int naser = 3999, tourist = 3816;
int power(int a, int b) { int ans = 1; while (b) { if (b % 2) ans *= a; a *= a; b /= 2; } return ans; }
long long ex[1001][1001], ti[1001][1001], y, x, n, m;
vint tmp, w, s;
vll t;
bool cmp(int a, int b) {
long double aa = -1;
if (w[a] != x)
aa = (y - t[a]) / (w[a] - x);
long double bb = -1;
if (w[b] != x)
bb = (y - t[b]) / (w[b] - x);
return aa < bb;
}
void init(int l, int N, vll T, vint W, int X, int M, vint S) {
t = T;
w = W;
s = S;
x = X;
n = N;
m = M;
tmp.resize(n);
for (int i = 0; i < m; i++)
ti[i][0] = t[i];
for (int j = 1; j < m; j++) {
for (int i = 0; i < n; i++) {
ex[i][j] = ti[i][j - 1] + (s[j] - s[j - 1]) * w[i];
}
for (int i = 0; i < n; i++) {
ti[i][j] = ex[i][j];
for (int k = 0; k < n; k++) {
if (ti[k][j - 1] < ti[i][j - 1])
ti[i][j] = max(ex[i][j], ex[k][j]);
}
}
}
for (int i = 0; i < n; i++)
tmp[i] = i;
}
long long arrival_time(long long Y) {
y = Y;
long long arrive[1001] = {};
sort(all(tmp), cmp);
int it = 1;
arrive[0] = y;
for (int i = 0; i < n; i++) {
if (w[tmp[i]] == x || w[tmp[i]] <= x || t[tmp[i]] >= y)
continue;
int cross = (arrive[it-1] - ti[tmp[i]][it - 1]) / (w[tmp[i]] - x) + ((arrive[it - 1] - ti[tmp[i]][it - 1]) % (w[tmp[i]] - x) != 0);
cross += s[it - 1];
int idx = lower_bound(all(s), cross) - s.begin();
while (it < m - 1 && it < idx) {
arrive[it] = arrive[it - 1] + (s[it] - s[it - 1]) * x;
it++;
}
if (idx == it && idx < m) {
arrive[it] = max(ti[tmp[i]][it], arrive[it - 1] + (s[it] - s[it - 1]) * x);
it++;
}
}
while (it < m) {
arrive[it] = arrive[it - 1] + (s[it] - s[it - 1]) * x;
it++;
}
return arrive[m - 1];
}
/*int32_t main() {
init(6, 4, { 20, 10, 40, 0 }, { 5, 20, 20, 30 }, 10, 4, { 0, 1, 3, 6 });
//init(6, 2, { 10, 20 }, { 5, 3 }, 2, 2, { 0, 6 });
while (naser > tourist) {
int y;
cin >> y;
cout << arrival_time(y) << endl;
}
}*/
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