이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
using pll = pair<long long, long long>;
#define ll long long
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define pb push_back
#define eb emplace_back
#define vi vector<ll>
#define vb vector<bool>
#define f0(i,a) for(ll i=0;i<(a);i++)
#define f1(i,a) for(ll i=1;i<(a);i++)
#define rep(i,a,b) for(int i=(a);i<=(b);++i)
#define per(i,a,b) for(int i=(a);i>=(b);--i)
#define f first
#define s second
template<typename A, typename B> ostream& operator<<(ostream &os, const pair<A, B> &p) { return os << '(' << p.first << ", " << p.second << ')'; }
template<typename T_container, typename T = typename enable_if<!is_same<T_container, string>::value, typename T_container::value_type>::type> ostream& operator<<(ostream &os, const T_container &v) { os << '{'; string sep; for (const T &x : v) os << sep << x, sep = ", "; return os << '}'; }
// http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2016/p0200r0.html
template<class Fun> class y_combinator_result {
Fun fun_;
public:
template<class T> explicit y_combinator_result(T &&fun): fun_(std::forward<T>(fun)) {}
template<class ...Args> decltype(auto) operator()(Args &&...args) { return fun_(std::ref(*this), std::forward<Args>(args)...); }
};
template<class Fun> decltype(auto) y_combinator(Fun &&fun) { return y_combinator_result<std::decay_t<Fun>>(std::forward<Fun>(fun)); }
#ifdef I_AM_NOOB
#define gg(...) [](const auto&...x){ char c='='; cerr<<#__VA_ARGS__; ((cerr<<exchange(c,',')<<x),...); cerr<<endl; }(__VA_ARGS__);
#else
#define gg(...) 777771449
#endif
constexpr ll INFF = 1e18;
constexpr ll P = 1e9+7;
// constexpr ll P = 998244353;
int main() {
cin.tie(0) -> ios::sync_with_stdio(0);
ll n, k; while (cin >> n >> k) {
ll x = n;
vi a(n+2);
f1(i, n+1) cin >> a[i];
set<pll> st;
vi mark(n+2, 1);
f1(i, n+1) {
if (i < n) st.insert({a[i+1] - a[i], i+1});
}
while (x-- > k) {
mark[(*st.begin()).s] = 0;
st.erase(st.begin());
}
ll cost = 0;
ll lst = 0;
f1(i, n+2) {
if(mark[i] == 1) {
if(lst != 0) {
cost += a[i-1] - lst + 1;
}
lst = a[i];
}
}
cout << cost << endl;
}
return 0;
}
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