제출 #844829

#제출 시각아이디문제언어결과실행 시간메모리
844829hamerinSalesman (IOI09_salesman)C++17
62 / 100
520 ms36704 KiB
#include <bits/stdc++.h> #pragma GCC optimize("Ofast") #pragma GCC optimize("unroll-loops") using namespace std; using li = long long; using ld = long double; using pi = pair<int, int>; using pli = pair<li, li>; #define all(c) c.begin(), c.end() #define prec(n) setprecision(n) << fixed template <typename T> class SegTree { public: uint N; vector<T> vl; explicit SegTree(uint _N) : N(_N), vl(N << 2, numeric_limits<T>::min() / T(2)) {} void update(uint s, uint e, uint n, uint t, T x) { if (t < s || e < t) return; if (s == e) { vl[n] = x; return; } uint m = (s + e) >> 1, k = n << 1; update(s, m, k, t, x); update(m + 1, e, k | 1, t, x); vl[n] = max(vl[k], vl[k | 1]); } T query(uint s, uint e, uint n, uint l, uint r) { if (r < s || e < l) return numeric_limits<T>::min() / T(2); if (l <= s && e <= r) return vl[n]; uint m = (s + e) >> 1, k = n << 1; return max(query(s, m, k, l, r), query(m + 1, e, k | 1, l, r)); } inline void update(uint t, T x) { update(0, N - 1, 1, t, x); } inline T query(uint l, uint r) { return query(0, N - 1, 1, l, r); } }; int main() { ios_base::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr); int N, U, D, S; cin >> N >> U >> D >> S; vector<int> locs(1, S); vector<tuple<int, int, int>> markets; markets.emplace_back(0, S, 0); markets.emplace_back(500001, S, 0); for (int i = 0; i < N; i++) { int T, L, M; cin >> T >> L >> M; markets.emplace_back(T, L, M); locs.emplace_back(L); } sort(all(locs)), locs.erase(unique(all(locs)), locs.end()); sort(all(markets)); vector<int> res; SegTree<int> upper((uint)locs.size()), lower((uint)locs.size()); for (auto [T, L, M] : markets) { const int Lc = lower_bound(all(locs), L) - locs.begin(); if (T == 0) { res.emplace_back(M); upper.update(Lc, -U * L); lower.update(Lc, D * L); continue; } res.emplace_back(max(upper.query(Lc, (uint)locs.size() - 1) + U * L, lower.query(0, Lc) - D * L) + M); upper.update(Lc, res.back() - U * L); lower.update(Lc, res.back() + D * L); } cout << res.back() << '\n'; return 0; }
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